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andreadesirepen Group TitleBest ResponseYou've already chosen the best response.0
i know it´s exponential
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
It seems like the line y = 1 is a horizontal asymptote. Apart from that, it looks like an exponential function, so my first guess would be: f(x)= 1+ a^x. Maybe if you read off a few points on the graph, you could determine a.
 one year ago

andreadesirepen Group TitleBest ResponseYou've already chosen the best response.0
a=2
 one year ago

andreadesirepen Group TitleBest ResponseYou've already chosen the best response.0
is it 2^x+2 ?
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
OOps, the unit is 2 on the axes...so it is f(x)=2+a^x
 one year ago

BenjaminEE Group TitleBest ResponseYou've already chosen the best response.0
It looks like a^x, but since the left sides converges towards 2 and not 0 it looks more like: y = 2+c*a^x y(2) seems to be about 6 y(0) seems to be about 2.5 y(0) = 2.5 => 1 + c*a^0 = 1 + c c = 1.5: y(2) = 1 + 1.5*a^2 = 6 1.5*a^2 = 5 a = sqrt( 5/1.5 ) ~ 1.8 all in all, y = 2 + 1.5 * 1.8^x
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
Now, let's see if I can read off the number a: if I move it down 2 units, it goes through (0,1). Also it would go through (2, 4), so a²=4/1=4. That means a=2. I think you have found the answer already!
 one year ago

andreadesirepen Group TitleBest ResponseYou've already chosen the best response.0
thanks!
 one year ago

ZeHanz Group TitleBest ResponseYou've already chosen the best response.1
@BenjaminEE: seems you made an error reading off the value for y=0... (unit = 2 on the axes)
 one year ago

BenjaminEE Group TitleBest ResponseYou've already chosen the best response.0
@ZeHanz Oh I see. Thanks for correcting me.
 one year ago
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