A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
what function is represented?
anonymous
 3 years ago
what function is represented?

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know it´s exponential

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.1It seems like the line y = 1 is a horizontal asymptote. Apart from that, it looks like an exponential function, so my first guess would be: f(x)= 1+ a^x. Maybe if you read off a few points on the graph, you could determine a.

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.1OOps, the unit is 2 on the axes...so it is f(x)=2+a^x

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It looks like a^x, but since the left sides converges towards 2 and not 0 it looks more like: y = 2+c*a^x y(2) seems to be about 6 y(0) seems to be about 2.5 y(0) = 2.5 => 1 + c*a^0 = 1 + c c = 1.5: y(2) = 1 + 1.5*a^2 = 6 1.5*a^2 = 5 a = sqrt( 5/1.5 ) ~ 1.8 all in all, y = 2 + 1.5 * 1.8^x

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.1Now, let's see if I can read off the number a: if I move it down 2 units, it goes through (0,1). Also it would go through (2, 4), so a²=4/1=4. That means a=2. I think you have found the answer already!

ZeHanz
 3 years ago
Best ResponseYou've already chosen the best response.1@BenjaminEE: seems you made an error reading off the value for y=0... (unit = 2 on the axes)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@ZeHanz Oh I see. Thanks for correcting me.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.