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sara1234

  • one year ago

HELP ME PLZ

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  1. seiga
    • one year ago
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    why dont u use mathway.com it helps?!

  2. sara1234
    • one year ago
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    i know how to do this but i don't know why i keep getting a wrong answer?

  3. seiga
    • one year ago
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    okay what did u get....go step by step.?

  4. sara1234
    • one year ago
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    i got this 1.5159=(4+r)^(44)

  5. seiga
    • one year ago
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    hold on lemme see...

  6. seiga
    • one year ago
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    i think its 3.8

  7. sara1234
    • one year ago
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    can you show me what you did ?

  8. seiga
    • one year ago
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    i was guessing lmao i hate math!

  9. seiga
    • one year ago
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    sorry:/

  10. seiga
    • one year ago
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    wait i think i got it....wait

  11. sara1234
    • one year ago
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    what you get?

  12. sara1234
    • one year ago
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    anyone can show me how to solve this? 2976.45=1963.45(1+r/4)^4(11)

  13. tcarroll010
    • one year ago
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    You have an equation of the form: a = b(x^n) That will equal: a/b = x^n -> ln(a/b) = ln(x^n) -> ln(a/b) = n times ln(x) [ln(a/b)] / n = ln (x) e^( [ln(a/b)] / n ) = e^[ln(x)] = x "x" is your expression in parentheses, the 1 + a quarter of the rate.

  14. sara1234
    • one year ago
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    what is that?? the formula i wrote is correct

  15. tcarroll010
    • one year ago
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    Yes, your formula is correct and it matches mine. I am just using a general symbol method. For you to do some work here, you only have to make the substitutions and solve.

  16. sara1234
    • one year ago
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    i dont understand that can you please just show me how to solve that formula i did it several times and got a wrong answer PLEASEE i beg you im so tired

  17. tcarroll010
    • one year ago
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    You can do this! 2976.45=1963.45(1+r/4)^4(11) a = 2976.45, b = 1963.45, n = 44 Just make those substitutions and follow my solution method. Just plug in and follow the steps. Just try it. If you are that tired, I can give you a little more, but we tutors can't just give answers, we are required to show students how to solve and and top of it the students are supposed to do the work. I'll help as much as I can, but I can't just give ans answer.

  18. tcarroll010
    • one year ago
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    Start by dividing both sides by what "b" is. It will start to isolate that exponential expression on the right-hand side.

  19. sara1234
    • one year ago
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    i didd this many timessss im telling youu i just want to see where i went wrong i end up with 1.5159=5+r

  20. sara1234
    • one year ago
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    ^44

  21. sara1234
    • one year ago
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    1.5159=(1+r/4)^4*11

  22. sara1234
    • one year ago
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    then- 1.5159=5+r^44 im not sure about 5 than what do i doo

  23. tcarroll010
    • one year ago
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    Good so far, keep going.

  24. tcarroll010
    • one year ago
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    Wait, hold on.

  25. tcarroll010
    • one year ago
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    This is where you went wrong. And before I show you, I just quickly want to say that doing it this way, you will learn. If I just did the steps, no way is anyone going to learn. This is learning by mistakes. Don't be afraid of mistakes. Now, The (1 + r/4) has to stay in parentheses for quite a while. Always respect the parentheses. They take precedence over the exponentiation. If you don't like that long expression in parentheses, call it "x" for now.

  26. tcarroll010
    • one year ago
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    So, I'll take over from here for a little while and give you a little break. Hold on while I type.

  27. tcarroll010
    • one year ago
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    1.5159286 = (1 + r/4)^44 ln 1.5159286 = ln [(1 + r/4)^44] = 44 times ln [(1 + r/4)] (ln 1.5159286) / 44 = ln [(1 + r/4)] e^[(ln 1.5159286) / 44] = e^(ln [(1 + r/4)]) = (1 + r/4)

  28. tcarroll010
    • one year ago
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    Are you still getting this or did you get lost anywhere along the way? Should I stop or go on?

  29. sara1234
    • one year ago
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    i dont understand the way you type i have all the steps in my paper can you just give me the second to last line of this problem so i can see if its the same i get 1.0094=4+r

  30. sara1234
    • one year ago
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    then i have to take away 4 from each side

  31. sara1234
    • one year ago
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    i keep getting an negative number

  32. tcarroll010
    • one year ago
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    ok, we'll do it that way. Hold on.

  33. sara1234
    • one year ago
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    1.5159^1/44=4+r^1/44 this is where i can stuck putting it to the power of ^1/44 i get 1.0094 which idk is right or not please help me fast its late

  34. tcarroll010
    • one year ago
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    e^[(ln 1.5159286) / 44] = e^(ln [(1 + r/4)]) = (1 + r/4) e^[(ln 1.5159286) / 44] - 1 = r/4 4(e^[(ln 1.5159286) / 44] - 1) = r The right side is the rate. The left side is: 0.03800011 That's 3.8%

  35. tcarroll010
    • one year ago
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    That's the annual rate. It's 4 times the quarterly rate of: 0.9500028 percent.

  36. sara1234
    • one year ago
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    so where did i go wrong

  37. tcarroll010
    • one year ago
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    I know it's late and you're tired, so tomorrow, you might want to go over all of this. I strongly recommend this. Good working with you and thx for the recognition. More importantly, just hang in there! You went wrong by taking that 1 + r/4 out of the parentheses. That stays in there until the very end.

  38. tcarroll010
    • one year ago
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    Fast? It's going to take me a while just to read it!

  39. sara1234
    • one year ago
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    thats fine

  40. tcarroll010
    • one year ago
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    Well, I got problem #11, it's "b", not "c" like you have it, but you were not far off.

  41. sara1234
    • one year ago
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    thanks

  42. tcarroll010
    • one year ago
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    #12 is quarterly, not monthly. I don't think you are getting this just yet. You need to practice this a lot more.

  43. sara1234
    • one year ago
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    these are practice problem i did like 50 and these are the ones i wasnt sure about

  44. sara1234
    • one year ago
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    i just want to know which ones i need to practice more

  45. sara1234
    • one year ago
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    how are 13 and 14 last two?

  46. sara1234
    • one year ago
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    im sure about the rest just not these 4

  47. tcarroll010
    • one year ago
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    You had #11 and #12 wrong and I got you right answers. I figured out #13 (didn't look at #14 yet). I need to see your work since you are not getting these right. Show me your work on #13.

  48. sara1234
    • one year ago
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    my work is on paper its going to take me a while to type but i think 13 is okay

  49. tcarroll010
    • one year ago
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    Yes, #13 is definitely 88.

  50. sara1234
    • one year ago
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    for 14 i think its wrong

  51. tcarroll010
    • one year ago
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    What is "n" and "an"? I don't get what those expressions mean. To do this problem, I need to know what "n" and "an" stand for.

  52. sara1234
    • one year ago
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    thats what im trying to figure out

  53. tcarroll010
    • one year ago
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    Not the values, what is the meaning of "n" and "an"? They stand for something even before we figure out the values.

  54. sara1234
    • one year ago
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    i think n is number of cells and an is days or vise versa thats what im trying to figure out

  55. sara1234
    • one year ago
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    i'll just go with A

  56. tcarroll010
    • one year ago
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    Hold, on I figured it out algebraically.

  57. tcarroll010
    • one year ago
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    I'm just trying to relate my answer back to the crazy notation in the problem.

  58. tcarroll010
    • one year ago
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    You're going to have to help with relating the answer back to the problem's notation, but here it is in how I look at it: For any day, starting with the 3rd day, that day's number of cells is: [2 x (# cells in previous day)] - (# cells in previous to previous day) + 3 "previous day" is "day - 1" "previous to previous day" is "day - 2" Making sense?

  59. sara1234
    • one year ago
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    yeah

  60. tcarroll010
    • one year ago
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    I checked this answer out up to 88, which is day 7. Can you get this back into that crazy notation?

  61. sara1234
    • one year ago
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    not really other than -1

  62. tcarroll010
    • one year ago
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    Well, I know my formula works like a charm. We could try together to get that into the notation from the problem, but I still don't know about that "an" and "n". Are you sure that that problem was written down right?

  63. tcarroll010
    • one year ago
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    While you're answering that, I'm working on that notation.

  64. sara1234
    • one year ago
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    its A for sure thanks for your help

  65. tcarroll010
    • one year ago
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    Yes, I just confirmed A. I figured out the notation, but you might want a bit of explanation on it.

  66. tcarroll010
    • one year ago
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    I don't know where that post of yours went, I don't see it anymore, but A was correct, for sure.

  67. tcarroll010
    • one year ago
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    Well! It looks like we're done! Nice working with you and good luck in everything!

  68. sara1234
    • one year ago
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    Your so nice thank you so much please keep in touch please

  69. tcarroll010
    • one year ago
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    And you're nice, too! You made my day! :-)

  70. tcarroll010
    • one year ago
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    btw, "an - 1" is the # of cells in the previous day, but I think you know that by now.

  71. tcarroll010
    • one year ago
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    And this was exhausting!

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