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to get the length and the width of rectangle of FGHJ, just multiply by 4 from the length and the width of rectangle ABCD. so, l = 4 * 5 = 20 w = 4 * 10 = 40 now, to get area use the formula : area = length * width = 20 * 40 = .... in
Thanks; let me read your reply.
It might take a few mins,ok?
for perimeter of rectangle FGHJ, use the formula : perimeter = 2(l+w) = 2(20+40) = 2 * 60 = ... in
yes, that's right sorry, the unit for area must be in squared not in :)
ok, thank u! so, how should I state my answer?
You can call me '123', by the way.
oppss.. my eyes still want to bed, @123 :) area = 20 * 40 = 80 in^2 not 60 (sorry) perimeter = 2(20+40) = 2(60) = 120 in
opss.. 20 * 40 = 800 not 80 my stupid --"
nope. so, what should i write for number 1?
oK. But 1 is asking how the area was affected by the dilation.
it can be : area = 16 times of the area of before do dilated
Oh,ok. Let me write that down .
or '16 times the original area'?
i told you that trick before, enchilada
I'm forgetful. SORRY. HAHHAHAHAHA
for area, you square the amount of times it changed. like, if the scale factor is 3, 3^2 = 9. so the area would be 9 times greater
if you're doing volume, you cube it
So the answer would be is 16 times larger than before?
yea, 16 times the original
Oh, I GET IT! I THINK. THANKS!
The perimeter is.
the perimeter would be 4 times greater
Is that a good drawing?
x is the scale factor. perimeter: x^1, area: x^2, volume: x^3
thanks. i get it, volume is cubed, area is squared. so the perimeter is .. um..
so since the scale factor is 4... 4^1 = 4. perimeter is 4x the original. is this making sense?
Ahhhh! I GET IT NOW! WOW. I'M SO SLOW. I APOLOGIZE TO YOU BOTH.