Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360985504635:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
a spring with k 170 N/m is at the top of a frictionless incline of angle 37.0°.The lower end of the incline is distance D 1.00 m from the end of the spring, which is at its relaxed length. A 2.00 kg canister is pushed against the spring until the spring is compressed 0.200 m and released from rest. (a) What is the speed of the canister at the instant the spring returns to its relaxed length (which is when the canister loses contact with the spring)? (b) What is the speed of the canister when it reaches the lower end of the incline?
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
what i did is dw:1360985802827:dw
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
use energy conservation in both cases. when compressed , E= kx^2/2 + mgh x=0.2m When it is at bottom h = (D+x)sin37
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
for h the total distance id 1m+.2m (compressed distance )
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
sin37(1.2)=h
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
yes you are proceeding correctly
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
if i solve it i got v=4.20m/s
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
is this right
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
no this will be the answer to part b i.e. the canister has reached the ground
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
(b) i got dw:1360986031295:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@Diwakar how can that be part b
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
you have calculated h corresponding to the lower end of the incline
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
it doest not matter right because i got height so the box is top so height works
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
dw:1360986099560:dw
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
oh sorry the height 1.2sin37 is from bottom to the cannister and not to the top of the incline as i have shown in the figure
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360986365438:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
u mean that
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
yes the black line shows the heigth 1.2 sin37
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
shouldnt that be 1sin 37 because the spring not compressed
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
for part a energy conservation will be dw:1360986436055:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360986652778:dw
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
u mean that right
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay for part b u need to use h=1.2sin37 and should we consider the part (a) speed as initial speed
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
dw:1360986763295:dw
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
you may do that here h = 1*sin37
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
since the body has already covered 0.2m in part a as it loses contact with the spring
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
for part b u mean
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay so h=1 sin 37 and i can use above equation right with initial speed from part (a)
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
@Diwakar
 one year ago

Diwakar Group TitleBest ResponseYou've already chosen the best response.1
yes for part b
 one year ago

ksaimouli Group TitleBest ResponseYou've already chosen the best response.0
okay thx very much
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.