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ksaimouliBest ResponseYou've already chosen the best response.0
dw:1360985504635:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
a spring with k 170 N/m is at the top of a frictionless incline of angle 37.0°.The lower end of the incline is distance D 1.00 m from the end of the spring, which is at its relaxed length. A 2.00 kg canister is pushed against the spring until the spring is compressed 0.200 m and released from rest. (a) What is the speed of the canister at the instant the spring returns to its relaxed length (which is when the canister loses contact with the spring)? (b) What is the speed of the canister when it reaches the lower end of the incline?
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
what i did is dw:1360985802827:dw
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
use energy conservation in both cases. when compressed , E= kx^2/2 + mgh x=0.2m When it is at bottom h = (D+x)sin37
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
for h the total distance id 1m+.2m (compressed distance )
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
yes you are proceeding correctly
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
if i solve it i got v=4.20m/s
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
no this will be the answer to part b i.e. the canister has reached the ground
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
(b) i got dw:1360986031295:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
@Diwakar how can that be part b
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
you have calculated h corresponding to the lower end of the incline
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
it doest not matter right because i got height so the box is top so height works
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
oh sorry the height 1.2sin37 is from bottom to the cannister and not to the top of the incline as i have shown in the figure
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1360986365438:dw
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
yes the black line shows the heigth 1.2 sin37
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
shouldnt that be 1sin 37 because the spring not compressed
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
for part a energy conservation will be dw:1360986436055:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1360986652778:dw
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
okay for part b u need to use h=1.2sin37 and should we consider the part (a) speed as initial speed
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1360986763295:dw
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
you may do that here h = 1*sin37
 one year ago

DiwakarBest ResponseYou've already chosen the best response.1
since the body has already covered 0.2m in part a as it loses contact with the spring
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
okay so h=1 sin 37 and i can use above equation right with initial speed from part (a)
 one year ago
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