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jairo.9
Group Title
I have this fraction z/((z+1)(z+2)) and I don´t know how to get this equivalence z/(z+1)z/(z+2) anyone could help me?
 one year ago
 one year ago
jairo.9 Group Title
I have this fraction z/((z+1)(z+2)) and I don´t know how to get this equivalence z/(z+1)z/(z+2) anyone could help me?
 one year ago
 one year ago

This Question is Open

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{z}{(z+1)}  \frac{z}{(z+2)}\]Make a common denominator: \[\frac{z}{(z+1)}*\frac{(z+2)}{(z+2)}  \frac{z}{(z+2)}*\frac{(z+1)}{(z+1)} = \frac{z^2 + 2z  z^2 z}{(z+1)(z+2)} = \frac{z}{(z+1)(z+2)} \]
 one year ago

jairo.9 Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your help, but I don't know how did you get this z(z+1)−z(z+2) from z(z+1)(z+2)???
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
I just showed you, didn't I? I went in the other direction, starting with the result and going back to the start.
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
If that makes you uncomfortable, you could use partial fractions to go from \[\frac{z}{(z+1)(z+2)} \rightarrow \frac{z}{(z+1)}\frac{z}{(z+2)}\]
 one year ago

jairo.9 Group TitleBest ResponseYou've already chosen the best response.0
but partial fractions gives me 2/(z+2)1/(z+1) and I couldn't get z/(z+1)z/(z+2)
 one year ago

jairo.9 Group TitleBest ResponseYou've already chosen the best response.0
Thanks I got it. thank for your help!!
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
What technique did you use?
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{2}{z+2}\frac{1}{z+1}\]Make a common denominator \[\frac{2}{(z+2)}*\frac{(z+1)}{(z+1)}  \frac{1}{(z+1)}*\frac{(z+2)}{(z+2)} = \frac{2(z+1)  (z+2)}{(z+1)(z+2)} = \frac{z}{(z+1)(z+2)}\]Now here's the trick: add antimatter! :) \[\frac{z}{(z+1)(z+2)} = \frac{z +z^2  z^2}{(z+1)(z+2)} = \frac{z(z+2)z(z+1)}{(z+1)(z+2)} =\]\[ \frac{z(z+2)}{(z+1)(z+2)} \frac{z(z+1)}{(z+1)(z+2)} = \frac{z}{z+2}\frac{z}{z+1}\]
 one year ago
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