Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
I have this fraction z/((z+1)(z+2)) and I don´t know how to get this equivalence z/(z+1)z/(z+2) anyone could help me?
 one year ago
 one year ago
I have this fraction z/((z+1)(z+2)) and I don´t know how to get this equivalence z/(z+1)z/(z+2) anyone could help me?
 one year ago
 one year ago

This Question is Open

whpalmer4Best ResponseYou've already chosen the best response.1
\[\frac{z}{(z+1)}  \frac{z}{(z+2)}\]Make a common denominator: \[\frac{z}{(z+1)}*\frac{(z+2)}{(z+2)}  \frac{z}{(z+2)}*\frac{(z+1)}{(z+1)} = \frac{z^2 + 2z  z^2 z}{(z+1)(z+2)} = \frac{z}{(z+1)(z+2)} \]
 one year ago

jairo.9Best ResponseYou've already chosen the best response.0
Thanks for your help, but I don't know how did you get this z(z+1)−z(z+2) from z(z+1)(z+2)???
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
I just showed you, didn't I? I went in the other direction, starting with the result and going back to the start.
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
If that makes you uncomfortable, you could use partial fractions to go from \[\frac{z}{(z+1)(z+2)} \rightarrow \frac{z}{(z+1)}\frac{z}{(z+2)}\]
 one year ago

jairo.9Best ResponseYou've already chosen the best response.0
but partial fractions gives me 2/(z+2)1/(z+1) and I couldn't get z/(z+1)z/(z+2)
 one year ago

jairo.9Best ResponseYou've already chosen the best response.0
Thanks I got it. thank for your help!!
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
What technique did you use?
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
\[\frac{2}{z+2}\frac{1}{z+1}\]Make a common denominator \[\frac{2}{(z+2)}*\frac{(z+1)}{(z+1)}  \frac{1}{(z+1)}*\frac{(z+2)}{(z+2)} = \frac{2(z+1)  (z+2)}{(z+1)(z+2)} = \frac{z}{(z+1)(z+2)}\]Now here's the trick: add antimatter! :) \[\frac{z}{(z+1)(z+2)} = \frac{z +z^2  z^2}{(z+1)(z+2)} = \frac{z(z+2)z(z+1)}{(z+1)(z+2)} =\]\[ \frac{z(z+2)}{(z+1)(z+2)} \frac{z(z+1)}{(z+1)(z+2)} = \frac{z}{z+2}\frac{z}{z+1}\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.