anonymous
  • anonymous
Factor 5x4 - 30x2 - 135. 5(x2+ 9)(x2- 3) *********** 5(x - 3)(x + 3)(x2- 3) I think it is the one with ******* 5(x - 3)(x + 3)(x2+ 3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
no sorry,its the last one \(5(x - 3)(x + 3)(x^2+ 3)\)
ParthKohli
  • ParthKohli
\[5(x^4 - 6x^2 - 27) = 5(x^4 - 9x^2 + 3x^2 - 27)\]
ParthKohli
  • ParthKohli
I think you can group the terms and factor.

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anonymous
  • anonymous
so it is the last one
campbell_st
  • campbell_st
this is an equation reducible to a quadratic take 5 as the common factor and then you have \[5(x^4 - 6x^2 - 27)\] which can be treated as \[5((x^2)^2 - 6(x^2) - 27)\]
anonymous
  • anonymous
yes @Shannon20150
anonymous
  • anonymous
will u help me again all of u

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