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Shannon20150

  • 3 years ago

Factor 5x4 - 30x2 - 135. 5(x2+ 9)(x2- 3) *********** 5(x - 3)(x + 3)(x2- 3) I think it is the one with ******* 5(x - 3)(x + 3)(x2+ 3)

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  1. yummydum
    • 3 years ago
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    no sorry,its the last one \(5(x - 3)(x + 3)(x^2+ 3)\)

  2. ParthKohli
    • 3 years ago
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    \[5(x^4 - 6x^2 - 27) = 5(x^4 - 9x^2 + 3x^2 - 27)\]

  3. ParthKohli
    • 3 years ago
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    I think you can group the terms and factor.

  4. Shannon20150
    • 3 years ago
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    so it is the last one

  5. campbell_st
    • 3 years ago
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    this is an equation reducible to a quadratic take 5 as the common factor and then you have \[5(x^4 - 6x^2 - 27)\] which can be treated as \[5((x^2)^2 - 6(x^2) - 27)\]

  6. yummydum
    • 3 years ago
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    yes @Shannon20150

  7. Shannon20150
    • 3 years ago
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    will u help me again all of u

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