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Shannon20150
Group Title
Factor the fourterm polynomial.
mn  15 + 3m  5n
(m + 3)(n  5)
(n  3)(m  5)
(n + 3)(m  5)
 one year ago
 one year ago
Shannon20150 Group Title
Factor the fourterm polynomial. mn  15 + 3m  5n (m + 3)(n  5) (n  3)(m  5) (n + 3)(m  5)
 one year ago
 one year ago

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Shannon20150 Group TitleBest ResponseYou've already chosen the best response.0
I think it is the 1st one
 one year ago

Shannon20150 Group TitleBest ResponseYou've already chosen the best response.0
okay how do u do it
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
You should multiply out each of those expressions...you need the practice!
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
The 1st one: \[(m+3)(n5) = mn 5m + 3n  15\]
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Let (m+x) (n+y) = mn  15 + 3m  5n => mn+ym+xn+xy=mn15+3m5n
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
U need to find x and y from there
 one year ago

whpalmer4 Group TitleBest ResponseYou've already chosen the best response.0
\[(a+b)(c+d) = a(c+d) + b(c+d) = ac + ad + bc + bd\] If you want to be clever, note that to get a +3m, you need to have a +3 multiply an m, and there's only one such equation.
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
comparing coffecients gives: x=5 and y=3
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
so, (m+x) (n+y) = mn  15 + 3m  5n = (m5)(n+3)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
got it
 one year ago

Shannon20150 Group TitleBest ResponseYou've already chosen the best response.0
so its the last one
 one year ago

Shannon20150 Group TitleBest ResponseYou've already chosen the best response.0
okay lol help me again please
 one year ago
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