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Shannon20150

  • one year ago

Factor the four-term polynomial. mn - 15 + 3m - 5n (m + 3)(n - 5) (n - 3)(m - 5) (n + 3)(m - 5)

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  1. Shannon20150
    • one year ago
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    I think it is the 1st one

  2. sauravshakya
    • one year ago
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    Nope

  3. Shannon20150
    • one year ago
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    okay how do u do it

  4. whpalmer4
    • one year ago
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    You should multiply out each of those expressions...you need the practice!

  5. whpalmer4
    • one year ago
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    The 1st one: \[(m+3)(n-5) = mn -5m + 3n - 15\]

  6. Shannon20150
    • one year ago
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    wat

  7. sauravshakya
    • one year ago
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    Let (m+x) (n+y) = mn - 15 + 3m - 5n => mn+ym+xn+xy=mn-15+3m-5n

  8. sauravshakya
    • one year ago
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    U need to find x and y from there

  9. whpalmer4
    • one year ago
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    \[(a+b)(c+d) = a(c+d) + b(c+d) = ac + ad + bc + bd\] If you want to be clever, note that to get a +3m, you need to have a +3 multiply an m, and there's only one such equation.

  10. sauravshakya
    • one year ago
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    comparing coffecients gives: x=-5 and y=3

  11. sauravshakya
    • one year ago
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    so, (m+x) (n+y) = mn - 15 + 3m - 5n = (m-5)(n+3)

  12. sauravshakya
    • one year ago
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    got it

  13. Shannon20150
    • one year ago
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    so its the last one

  14. sauravshakya
    • one year ago
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    yep

  15. Shannon20150
    • one year ago
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    okay lol help me again please

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