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Shannon20150
Group Title
Factor completely.
2k  k3  3k2
k(k + 1)(k  2)
k(k  1)(k  2)
k(k + 1)(k + 2)
 one year ago
 one year ago
Shannon20150 Group Title
Factor completely. 2k  k3  3k2 k(k + 1)(k  2) k(k  1)(k  2) k(k + 1)(k + 2)
 one year ago
 one year ago

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Callisto Group TitleBest ResponseYou've already chosen the best response.1
What is the common factor of the three terms there?
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Hmm.. One more.. Can you see the negative signs?
 one year ago

Shannon20150 Group TitleBest ResponseYou've already chosen the best response.0
is it the 2nd one
 one year ago

Callisto Group TitleBest ResponseYou've already chosen the best response.1
Yup! So, take out the common factor and group the rest of the terms. You'll get this: \[2k  k^3  3k^2\]\[=k(2+ k^2 + 3k)\]Rearrange the terms a bit: \[ = k (k^2+3k+2)\] From this, we can see that the 2nd one is nowhere near to the answer.
 one year ago
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