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|dw:1361001336066:dw|
(I suppose......)

Can you draw?

:P

wow you read my mind :D

:D

but. think.. the NET force = centripetal force !!

yeah I know thats the ending part

\[\LARGE F_{ca}=\frac{GM^2}{4R^2}\]

how did you get that bold equation???? and so big?? :O :O

|dw:1361001487972:dw|
(if im right...)

use the keyword large :P

ok that makes sense.. !! proceed with your calculation!

\[\LARGE F_{BC}=\frac{GM^2}{2R^2}\]
if im right........

\[\LARGE F_{CD}=\frac{GM^2}{2R^2}\]

yea correct.. now take vector sum of them!

now we gotta find resultant if we are correct till here

i guess so!.. proceed

2 at a time?

and your directions are wrong.. you are considering force ON c.. so opposite direction!

|dw:1361001778925:dw|
will it work out like this?

ah yeah sorry

sheehs what is that?? :O :O :O

|dw:1361001955102:dw|

think of a way to intelligently solve this!!

don't.. simply make it so complicated!!!

directions
\m/

its ok.. symmertry always works out :D.. so as long as it is symmetrical we are fine :D

??

now do the vector.. which two vectors if you take first.. it ll be easier to resolve??

WHY aren't we getting anything like this?
http://prntscr.com/sxhpz

we have diff values

its the same don't worry!! ... just proceed ... i gurantee yu.. its the same what we are doing!!

hmm kay so resultant thing..lets take AC and AB

okay lets study vectors first :P

:X.. go do that .. first then!

i meant "lets study" hmm nvm okay just tell me again :P

equalmag :o

so resultant is F/2?

nope.. two vecotrs.. mag F.. making 90 deg to each other.. ?? what is the value?

F/2?

wait

\[\LARGE \sqrt{A^2+A^2+2AAcos90}\]

yes.. what does that yield??

\[\LARGE \sqrt{2}A\]

yes.. now what will be the direction

:D :D
Im Einstein 8|

|dw:1361002507803:dw|

let me know when ur done with skype .-.

okay :(

90

v = (1/2) sqrt [ GM (1+ 2 sqrt2) / R]
is this the answer?

\[\LARGE V=\sqrt{\frac{GM}{R}(\frac{2 \sqrt{2}+1}{4}})\]

yeah

how did u get the answer O.O

Finding the resultant pellet

hold on. brb in 2 mins.

yeah i know arrow thin messed up

but Fcd and Fcb are not not providing centripetal force.
Fcdcos45 and Fcbcos45 are.
ellaborate? :o

yeah I do but applying this thing for the first time :)

can you show the 2 forces in the diagram?
just for some more clarification

|dw:1361004736715:dw|

confused

where are you confused?

^ that'll do!

http://www.troll.me/images/atomic-rage/chepo-fuuuuuuuuuu.jpg

good luck and have fun. :P

its the same.. one is by using i j k method.. one is by using mashy method lol :D

:|

tell me ijk

meanwhile posting the next Q:P

okay

yay one more medal :D

come to next one :P