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|dw:1361012885773:dw|

\[\LARGE \frac{2GM}{\sqrt{4L^2+d^2}}\]
is what I got one term seems missing

lol.. in such cases its better to take 2 diametrically opposite mass elements!

??

wait wait..lemme think!

no ..u wrote scary symbols :P

hmm. haha :P

|dw:1361026342375:dw|

ek se kyun nahi kar sakte O.O

|dw:1361026384089:dw|

you need to learn more vector analysis.. its a continous mass distribution!..

:/ what

yrelhan please explain..
dls whatever he said .. is exactly correct!

bolo na :/

what should i explain?

You can integrate more easily using an angular variable.

Can't you use similar triangles?

I have:
\(\LARGE \frac{2GM}{d\sqrt{L^2+4d^2}}\)

i didnt get d :/

i mean whats wrong with my method

The mass is a distance of
\[\LARGE \sqrt{L^2+\frac{d^2}{4}}\] from the rod

that would be complicated but eh

why are we considering elemental mass?

This is why I told you to use angle as integration variable.

okay..thanks :O but thats correct right?just complex..thanks!

Wait, I'll send the derivation.

Here it is.