Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
DeadShot
Group Title
What is the remainder when f(x) = x^3  14x^2 + 51x  22 is divided by x  7?
 one year ago
 one year ago
DeadShot Group Title
What is the remainder when f(x) = x^3  14x^2 + 51x  22 is divided by x  7?
 one year ago
 one year ago

This Question is Closed

Yahoo! Group TitleBest ResponseYou've already chosen the best response.2
According to RT. if xa is a factor then x  a = 0 x = 0 here x  7 = 0 x = 7 nw just find f(7)
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
so the remainder is 8, right?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
How can the remainder be a negative number?
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
i replaced x with 7, and the result was 8
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
it's not?
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
It is...
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
dw:1361015604329:dw
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Well, OK it's 8. But that is pretty trivial
 one year ago

DeadShot Group TitleBest ResponseYou've already chosen the best response.0
ok, i think i get it now, thanks!
 one year ago

Outkast3r09 Group TitleBest ResponseYou've already chosen the best response.0
\[f581\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.