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terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.2The rational root test... Given a polynomial with integer coefficients \[\large a_nx^n + a_{n1}x^{n1}....+a_1x+a_0\] If this polynomial is to have a rational root (zero), then it will ALWAYS be of the form \[\huge \pm \frac{p}{q}\] \[\large where \ p \ is \ a \ factor \ of \ a_0\]\[\large and \ q \ is \ a \ factor \ of \ a_n\]

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.2Lucky for you, it seems \[\huge a_n = 1\] This simplifies things...

DeadShot
 one year ago
Best ResponseYou've already chosen the best response.0so, if \[a _{n}=1\] ten how do i solve for \[a _{0}\] ?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.2You don't *solve* for \[\large a_0\]it's given. It's the last term in the polynomial, the constant, 15. What are the factors of 15?

DeadShot
 one year ago
Best ResponseYou've already chosen the best response.01, 3, 5, and 15, right?

terenzreignz
 one year ago
Best ResponseYou've already chosen the best response.2That's right. So those are the numerators if ever you're to have a rational root. But your leading coefficient is 1, so as I said, that simplifies things. What are your possible rational roots, then?

DeadShot
 one year ago
Best ResponseYou've already chosen the best response.0\[\pm1, \pm3, \pm5, and \pm15\] right?
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