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well if we take the man to reach more safely there is that is the first case

yeah @DLS has a point\

But we need to find the minimum V for that, he has to walk straight

|dw:1361020702285:dw|
We aren't given D, we can't find angle without it

|dw:1361020857966:dw|

sorry i took the distance 4m correct that value..

|dw:1361020933104:dw|

if my solution is close enough

how r those angles : 2 cot theta and 2 cosec theta ?

\[\LARGE \frac{12+2\cot \theta}{8}=\frac{8}{v}=\frac{6+\cot \theta}{4}\]

final thing

How do you have 8/v?
man isn't travelling 8 meters

V=s/t

|dw:1361021378137:dw|

yeah i got ur query,hold on

I solved this, there is no global minima for v.
We need to revisit the problem

got to go now,,,... sorry but please post your opinions

sure

i thought that was 2 cosec theta :O

Yes, if you solve the square root, you will get 2 cosec theta

:D

I'm not convinced about the car travelling an extra distance 2 cot theta

@mathslover do you have answer for this?

offline~

Just do the whole thing for him :P From the beginning :D

yep --- 4/3 --- ans..

bahhhh!!!!..

doing all that other crap!! :P.. good thing you put up the answer!!

4/3 is the simple method.. of going straight :O..

@mathslover Use my first post, I had told you for minimum it has to be straight

DLS can you tell me how you got 2 cot theta there ?

hold on

|dw:1361184323999:dw|
ok :)

isnt the sol clear?
they are taking for it to be going straight

But I am trying to do for the angle theta... please tell how you got 2 cot theta there

??

wait I got confused :P sec

|dw:1361185375230:dw|
AC=2 cot theta

\[\LARGE \cot \theta=\frac{1}{\tan \theta}\]

idk why i got confused !

\[\LARGE \cot \theta=\frac{AC}{2}\]

OH got it thanks a lot

:P