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what are those words??..can you explain why come up of that solution?
n! = n*(n-1)*(n-2)*...*3*2*1
There are 8 letters. To make words, you put the letters down, one by one. The first one can be chosen in 8 ways. The second in 7 ways. You've got 8*7 =56 possibilities already! This continues all the way down to the last letter. So you have 8*7*6*5*4*3*2*1 possibilities. The mathematical notation for this is 8!
One problem to solve: there are 2 E's so we have counted too much. We have to divide by the number of same possibilities if the two E's are switched. This switching of E's can be done in 2*1 = 2! ways. End result: 8!/2! = 20160
are you sure of that??
Surprising many, isnt it?
Sure I'm sure!
If you read carefully what I wrote, you'll come to the same conclusion. There is no escape. There are surprisingly many ways to make words with 8 letters...
Of course, most words would be difficult to pronounce and without meaning. Nevertheless, there are 20160 possibilities, If you find that hard to grasp, just try with fewer letters: If you have 1 letter, you can make only one "word". With 2 letters, the firat one can be chosen from 2, the second has only one possibility. So: 2*1 3 letters: 3*2*1 = 6 4: 4*3*2*1 = 24 It goes up really fast!
ok..thanks,now i understand..