anonymous
  • anonymous
how many different words can be formed from the word COMPLETE?..
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
8!/2!
anonymous
  • anonymous
what are those words??..can you explain why come up of that solution?
anonymous
  • anonymous
n! = n*(n-1)*(n-2)*...*3*2*1

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ZeHanz
  • ZeHanz
There are 8 letters. To make words, you put the letters down, one by one. The first one can be chosen in 8 ways. The second in 7 ways. You've got 8*7 =56 possibilities already! This continues all the way down to the last letter. So you have 8*7*6*5*4*3*2*1 possibilities. The mathematical notation for this is 8!
ZeHanz
  • ZeHanz
One problem to solve: there are 2 E's so we have counted too much. We have to divide by the number of same possibilities if the two E's are switched. This switching of E's can be done in 2*1 = 2! ways. End result: 8!/2! = 20160
anonymous
  • anonymous
are you sure of that??
ZeHanz
  • ZeHanz
Surprising many, isnt it?
anonymous
  • anonymous
@ZeHanz are you sure??
ZeHanz
  • ZeHanz
Sure I'm sure!
ZeHanz
  • ZeHanz
If you read carefully what I wrote, you'll come to the same conclusion. There is no escape. There are surprisingly many ways to make words with 8 letters...
anonymous
  • anonymous
20160 words??
ZeHanz
  • ZeHanz
Of course, most words would be difficult to pronounce and without meaning. Nevertheless, there are 20160 possibilities, If you find that hard to grasp, just try with fewer letters: If you have 1 letter, you can make only one "word". With 2 letters, the firat one can be chosen from 2, the second has only one possibility. So: 2*1 3 letters: 3*2*1 = 6 4: 4*3*2*1 = 24 It goes up really fast!
anonymous
  • anonymous
ok..thanks,now i understand..
ZeHanz
  • ZeHanz
YW!

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