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Rearrange it to become
2x^2+4x - 16 = 0
Then plug it into the formula or factor it

You can factor out a 2, see where that gets you..

Do you get it?

no,I don't

it becomes
2(x^2 + 2x - 8) = 0
when you factor it

Can you factor x^2 + 2x - 8 ?

okay let me try this

it would be (x+4)(x-2) right?

Do you know the formula? The quadratic formula?

Yes and no, I forgot the steps

Nice you factored it right

So then I would plug the x+4 and x-2 into the equation right,? it would be 2(4)^2+4(-2)=16??

2x-2=0 and 2x+4=0

oh wow, that was really simple, Now I under stand

Yay!! :)

Thank u

you're welcome