Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ihavemathquestions Group Title

Solve the compound inequality. Graph the solution. –8 ≤ 2x – 4 < 2

  • one year ago
  • one year ago

  • This Question is Closed
  1. ihavemathquestions Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    • one year ago
    1 Attachment
  2. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    I would leave the -8 and add the 4 from the 2x-4 to the <2 What would you get?

    • one year ago
  3. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    That's only the first step(:

    • one year ago
  4. ihavemathquestions Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2x < 2

    • one year ago
  5. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    Not quite. |dw:1361036597370:dw| Then what would you do?

    • one year ago
  6. ihavemathquestions Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    2x <14

    • one year ago
  7. ihavemathquestions Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    -2 ≤ x 3

    • one year ago
  8. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    It's a double inequality so it's going to look like\[[ ] \le x <[ ]\]

    • one year ago
  9. completeidiot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1361036836187:dw|

    • one year ago
  10. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so you need to get x by itself, to do that you have to divide everything by 2. |dw:1361036855393:dw| Then what would you get?

    • one year ago
  11. completeidiot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    kitt, you made a mistake, you cant just add 4 to the right side and middle you must do it to the entire inequality including the left side this would of course change the answer you gave

    • one year ago
  12. completeidiot Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @ihavemathquestions kitt's process if fine except for the 1st step just follow it can you'll get the answer

    • one year ago
  13. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1361037094501:dw|

    • one year ago
  14. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    so if you dived that out you should get the right answer(: the inequality signs don't change because you aren't multiplying or dividing by a negative number.

    • one year ago
  15. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    @completeidiot thank you for catching my mistake.

    • one year ago
  16. Kitt020912 Group Title
    Best Response
    You've already chosen the best response.
    Medals 0

    (:

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.