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YeseniaLopez
 2 years ago
To find the midpoint of a segment using the coordinates of its endpoints:
Answers:
A Calculate the average of the xcoordinates and the average of the ycoordinates of the endpoints.
B Calculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints.
CCalculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints and divide each by 2.
DCalculate the average of the xcoordinates and the average of the ycoordinates of the endpoints and divide each by 2.
YeseniaLopez
 2 years ago
To find the midpoint of a segment using the coordinates of its endpoints: Answers: A Calculate the average of the xcoordinates and the average of the ycoordinates of the endpoints. B Calculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints. CCalculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints and divide each by 2. DCalculate the average of the xcoordinates and the average of the ycoordinates of the endpoints and divide each by 2.

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whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1@iamforeveryoung D is incorrect. Read it carefully...

iamforeveryoung
 2 years ago
Best ResponseYou've already chosen the best response.0I reread it...@whpalmer4, yeah im wrong

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Here is how you can reason this out: Imagine you have a point at (0,0) and (0,a). What is the midpoint? Well, it is halfway along the line between (0,0) and (0,a), at (0,a/2). Now imagine you have a point at (0,0) and (a,0). What is the midpoint? Again, it is halfway along the line between (0,0) and (a,0), at (a/2, 0). Now imagine that you had points at (0,0) and (a,a). What is the midpoint? It is just the average of the x values, the average of the y values. (a/2, a/2). If you draw a picture, you can see this is true. You're just finding the midpoint for each axis, then combining them. dw:1361070601256:dw

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.1Hopefully it is clear that we are averaging the components, not just dividing one of them by 2 :)
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