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To find the midpoint of a segment using the coordinates of its endpoints:
Answers:
A Calculate the average of the xcoordinates and the average of the ycoordinates of the endpoints.
B Calculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints.
CCalculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints and divide each by 2.
DCalculate the average of the xcoordinates and the average of the ycoordinates of the endpoints and divide each by 2.
 one year ago
 one year ago
To find the midpoint of a segment using the coordinates of its endpoints: Answers: A Calculate the average of the xcoordinates and the average of the ycoordinates of the endpoints. B Calculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints. CCalculate the differences of the xcoordinates and the differences of the ycoordinates of the endpoints and divide each by 2. DCalculate the average of the xcoordinates and the average of the ycoordinates of the endpoints and divide each by 2.
 one year ago
 one year ago

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whpalmer4Best ResponseYou've already chosen the best response.1
@iamforeveryoung D is incorrect. Read it carefully...
 one year ago

iamforeveryoungBest ResponseYou've already chosen the best response.0
I reread it...@whpalmer4, yeah im wrong
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
Here is how you can reason this out: Imagine you have a point at (0,0) and (0,a). What is the midpoint? Well, it is halfway along the line between (0,0) and (0,a), at (0,a/2). Now imagine you have a point at (0,0) and (a,0). What is the midpoint? Again, it is halfway along the line between (0,0) and (a,0), at (a/2, 0). Now imagine that you had points at (0,0) and (a,a). What is the midpoint? It is just the average of the x values, the average of the y values. (a/2, a/2). If you draw a picture, you can see this is true. You're just finding the midpoint for each axis, then combining them. dw:1361070601256:dw
 one year ago

whpalmer4Best ResponseYou've already chosen the best response.1
Hopefully it is clear that we are averaging the components, not just dividing one of them by 2 :)
 one year ago
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