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How do I put that into a function and graph it
The time a clock shows \(n\) hours after 12 o'clock is \(12 + n \) modulo 12.
I hate to be a pain but could you give me an example please
\(n\) is your input and \(12 + n\) modulo 12 is the output. If you want the time shown on the clock \(4\) hours after \(12\), then you must calculate the remainder you get when you divide \(12 + 4\) by \(12\), which is \(4\).
Be honest: am I being of any help here? :-)
Yes, I am trying to see if I am doing it correctly. But I cant understand why we divide by 12
It's a long concept. Have you heard of clock-12 arithmetic?
Well, it goes like this: If you wanna add two given times on the clock, you must first add them, then calculate the "extra" amount you got there after 12. So if you wanna add 6 to 7 o'clock, it won't be 13 o'clock. It'd be 1 o'clock instead because you are 1 "extra" after 12.
OK, but you do understand that time on the clock keeps repeating right?
Yes I understand that and I know that cos and sin do also, but I cant express it in terms of a function
What if you want to know the time after \(x\) hours after \(12\) o'clock?
Not sure what you mean
After an hour, it is \(1\) o'clock. After two, it is \(2\) o'clock. You can make a table. y x 1 1 2 2 3 3 4 4 . . . . 1 13
Okay, i think i know where I am confused. I do not add 24 hours, I stop after 12 hours and and start over again
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