Ace school

with brainly

  • Get help from millions of students
  • Learn from experts with step-by-step explanations
  • Level-up by helping others

A community for students.

Can someone give me a real world example of a periodic function

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

the clock.
How do I put that into a function and graph it
The time a clock shows \(n\) hours after 12 o'clock is \(12 + n \) modulo 12.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I hate to be a pain but could you give me an example please
\(n\) is your input and \(12 + n\) modulo 12 is the output. If you want the time shown on the clock \(4\) hours after \(12\), then you must calculate the remainder you get when you divide \(12 + 4\) by \(12\), which is \(4\).
Be honest: am I being of any help here? :-)
Yes, I am trying to see if I am doing it correctly. But I cant understand why we divide by 12
It's a long concept. Have you heard of clock-12 arithmetic?
no
Well, it goes like this: If you wanna add two given times on the clock, you must first add them, then calculate the "extra" amount you got there after 12. So if you wanna add 6 to 7 o'clock, it won't be 13 o'clock. It'd be 1 o'clock instead because you are 1 "extra" after 12.
OK, but you do understand that time on the clock keeps repeating right?
Yes I understand that and I know that cos and sin do also, but I cant express it in terms of a function
What if you want to know the time after \(x\) hours after \(12\) o'clock?
Not sure what you mean
After an hour, it is \(1\) o'clock. After two, it is \(2\) o'clock. You can make a table. y x 1 1 2 2 3 3 4 4 . . . . 1 13
Okay, i think i know where I am confused. I do not add 24 hours, I stop after 12 hours and and start over again
I ♥ Mathematics..... Thanks To Her..... Do To Her Love For Me, I started LOVING Mathematics...
*Due

Not the answer you are looking for?

Search for more explanations.

Ask your own question