anonymous
  • anonymous
Can someone give me a real world example of a periodic function
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
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ParthKohli
  • ParthKohli
the clock.
anonymous
  • anonymous
How do I put that into a function and graph it
ParthKohli
  • ParthKohli
The time a clock shows \(n\) hours after 12 o'clock is \(12 + n \) modulo 12.

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anonymous
  • anonymous
I hate to be a pain but could you give me an example please
ParthKohli
  • ParthKohli
\(n\) is your input and \(12 + n\) modulo 12 is the output. If you want the time shown on the clock \(4\) hours after \(12\), then you must calculate the remainder you get when you divide \(12 + 4\) by \(12\), which is \(4\).
ParthKohli
  • ParthKohli
Be honest: am I being of any help here? :-)
anonymous
  • anonymous
Yes, I am trying to see if I am doing it correctly. But I cant understand why we divide by 12
ParthKohli
  • ParthKohli
It's a long concept. Have you heard of clock-12 arithmetic?
anonymous
  • anonymous
no
ParthKohli
  • ParthKohli
Well, it goes like this: If you wanna add two given times on the clock, you must first add them, then calculate the "extra" amount you got there after 12. So if you wanna add 6 to 7 o'clock, it won't be 13 o'clock. It'd be 1 o'clock instead because you are 1 "extra" after 12.
ParthKohli
  • ParthKohli
OK, but you do understand that time on the clock keeps repeating right?
anonymous
  • anonymous
Yes I understand that and I know that cos and sin do also, but I cant express it in terms of a function
ParthKohli
  • ParthKohli
What if you want to know the time after \(x\) hours after \(12\) o'clock?
anonymous
  • anonymous
Not sure what you mean
ParthKohli
  • ParthKohli
After an hour, it is \(1\) o'clock. After two, it is \(2\) o'clock. You can make a table. y x 1 1 2 2 3 3 4 4 . . . . 1 13
anonymous
  • anonymous
Okay, i think i know where I am confused. I do not add 24 hours, I stop after 12 hours and and start over again
goformit100
  • goformit100
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goformit100
  • goformit100
*Due

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