## dizliz24 2 years ago Can someone give me a real world example of a periodic function

1. ParthKohli

the clock.

2. dizliz24

How do I put that into a function and graph it

3. ParthKohli

The time a clock shows \(n\) hours after 12 o'clock is \(12 + n \) modulo 12.

4. dizliz24

I hate to be a pain but could you give me an example please

5. ParthKohli

\(n\) is your input and \(12 + n\) modulo 12 is the output. If you want the time shown on the clock \(4\) hours after \(12\), then you must calculate the remainder you get when you divide \(12 + 4\) by \(12\), which is \(4\).

6. ParthKohli

Be honest: am I being of any help here? :-)

7. dizliz24

Yes, I am trying to see if I am doing it correctly. But I cant understand why we divide by 12

8. ParthKohli

It's a long concept. Have you heard of clock-12 arithmetic?

9. dizliz24

no

10. ParthKohli

Well, it goes like this: If you wanna add two given times on the clock, you must first add them, then calculate the "extra" amount you got there after 12. So if you wanna add 6 to 7 o'clock, it won't be 13 o'clock. It'd be 1 o'clock instead because you are 1 "extra" after 12.

11. ParthKohli

OK, but you do understand that time on the clock keeps repeating right?

12. dizliz24

Yes I understand that and I know that cos and sin do also, but I cant express it in terms of a function

13. ParthKohli

What if you want to know the time after \(x\) hours after \(12\) o'clock?

14. dizliz24

Not sure what you mean

15. ParthKohli

After an hour, it is \(1\) o'clock. After two, it is \(2\) o'clock. You can make a table. y x 1 1 2 2 3 3 4 4 . . . . 1 13

16. dizliz24

Okay, i think i know where I am confused. I do not add 24 hours, I stop after 12 hours and and start over again

17. goformit100

I ♥ Mathematics..... Thanks To Her..... Do To Her Love For Me, I started LOVING Mathematics...

18. goformit100

*Due