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## anonymous 3 years ago integral 1 / [(x^2)sqrt(16-x^2)]

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1. hartnn

@lands91 Hi :) $$\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile$$ for your integral, have you tried the standard substitution for $$\sqrt{a^2-x^2}$$ as x = a sin t ?? here , try to put x = 4 sin t

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