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lands91

  • 3 years ago

integral 1 / [(x^2)sqrt(16-x^2)]

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  1. hartnn
    • 3 years ago
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    @lands91 Hi :) \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\) for your integral, have you tried the standard substitution for \(\sqrt{a^2-x^2}\) as x = a sin t ?? here , try to put x = 4 sin t

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