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JenniferSmart1
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How does \(\Delta V\) and \(\Delta U\)have the same magnitude for a given charge, when the change in U the integral multiplied by Q?
 one year ago
 one year ago
JenniferSmart1 Group Title
How does \(\Delta V\) and \(\Delta U\)have the same magnitude for a given charge, when the change in U the integral multiplied by Q?
 one year ago
 one year ago

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JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
\[\Delta V=V_bV_a=\frac{\Delta U}{q_0}=\int_a^b\vec E \cdot d\vec l\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
we'll I'm being told that "changes in U and V have the same magnitude for a given charge; they only depend on E.dl (the dot product of each differential path vector with the electric field)" and I don't understand how U and V can have the same magnitude
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
are we ignoring the test charge (q)?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
maybe the test charge is one unit
 one year ago
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