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 one year ago
How does \(\Delta V\) and \(\Delta U\)have the same magnitude for a given charge, when the change in U the integral multiplied by Q?
 one year ago
How does \(\Delta V\) and \(\Delta U\)have the same magnitude for a given charge, when the change in U the integral multiplied by Q?

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JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0\[\Delta V=V_bV_a=\frac{\Delta U}{q_0}=\int_a^b\vec E \cdot d\vec l\]

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0we'll I'm being told that "changes in U and V have the same magnitude for a given charge; they only depend on E.dl (the dot product of each differential path vector with the electric field)" and I don't understand how U and V can have the same magnitude

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0are we ignoring the test charge (q)?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0maybe the test charge is one unit
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