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JenniferSmart1 Group Title

How does \(\Delta V\) and \(\Delta U\)have the same magnitude for a given charge, when the change in U the integral multiplied by Q?

  • one year ago
  • one year ago

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  1. JenniferSmart1 Group Title
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    \[\Delta V=V_b-V_a=\frac{\Delta U}{q_0}=-\int_a^b\vec E \cdot d\vec l\]

    • one year ago
  2. JenniferSmart1 Group Title
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    we'll I'm being told that "changes in U and V have the same magnitude for a given charge; they only depend on E.dl (the dot product of each differential path vector with the electric field)" and I don't understand how U and V can have the same magnitude

    • one year ago
  3. JenniferSmart1 Group Title
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    are we ignoring the test charge (q)?

    • one year ago
  4. UnkleRhaukus Group Title
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    maybe the test charge is one unit

    • one year ago
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