A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
Why is this true?
\[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)=E dx\]
I understand the first part
\[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)\] but how does that equal Edx?
 2 years ago
Why is this true? \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)=E dx\] I understand the first part \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)\] but how does that equal Edx?

This Question is Closed

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1@zepdrix @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i and j are perpendicular i and k are perpendicular

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i.i = i^2 = 1 i.j =0 i.k=0

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1I'm sorry...but how did you determine that they were perpendicular?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i , j and k are standard unit vectors. i is along x direction j is along y direction k is along z direction and axes are perpendicular to each other, right ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1361080799293:dw any more doubts ?

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1ahhhh.....nope...no more doubts =D
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.