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JenniferSmart1

  • one year ago

Why is this true? \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)=E dx\] I understand the first part \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)\] but how does that equal Edx?

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  1. JenniferSmart1
    • one year ago
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    @zepdrix @hartnn

  2. hartnn
    • one year ago
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    i and j are perpendicular i and k are perpendicular

  3. hartnn
    • one year ago
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    i.i = i^2 = 1 i.j =0 i.k=0

  4. JenniferSmart1
    • one year ago
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    I'm sorry...but how did you determine that they were perpendicular?

  5. hartnn
    • one year ago
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    i , j and k are standard unit vectors. i is along x direction j is along y direction k is along z direction and axes are perpendicular to each other, right ?

  6. JenniferSmart1
    • one year ago
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    yes

  7. hartnn
    • one year ago
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    |dw:1361080799293:dw| any more doubts ?

  8. JenniferSmart1
    • one year ago
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    ahhhh.....nope...no more doubts =D

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