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JenniferSmart1
 2 years ago
Why is this true?
\[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)=E dx\]
I understand the first part
\[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)\] but how does that equal Edx?
JenniferSmart1
 2 years ago
Why is this true? \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)=E dx\] I understand the first part \[\vec E \cdot d \vec l=E \hat i \cdot (dx \hat i +dy \hat j +dz \hat k)\] but how does that equal Edx?

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JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1@zepdrix @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i and j are perpendicular i and k are perpendicular

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i.i = i^2 = 1 i.j =0 i.k=0

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1I'm sorry...but how did you determine that they were perpendicular?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i , j and k are standard unit vectors. i is along x direction j is along y direction k is along z direction and axes are perpendicular to each other, right ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1361080799293:dw any more doubts ?

JenniferSmart1
 2 years ago
Best ResponseYou've already chosen the best response.1ahhhh.....nope...no more doubts =D
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