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dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361089150658:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361089181888:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1or would it be cos^xcos5x

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0no cant combine them...it would just be \[\cos(5x)  \cos^{2} x \cos(5x)\]

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1so left integral is easy

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1hmm no i cant do that

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1that 5x is just blowing my mind

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0yeah im not sure of way to do it without expanding out the cos(5x) ..... which would be messy

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2huh ? integral of cos 5x is just sin 5x/5 +c .

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361089595564:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1yA i know that integral, but its the cos^2 that is messin me up

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2ok, you need to used \(\sin^2x = (1 \cos2x )/2\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2then, for cos 2x cos 7x there is a standard formula for , cos A cos B =...

dumbcow
 one year ago
Best ResponseYou've already chosen the best response.0ahh i always forget sum to product rules ... anyway, here is solution http://www.wolframalpha.com/input/?i=integrate+sin^2%28x%29+cos%285x%29+dx

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361090139384:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1ok so here is another, im thinking with this one i can multiply by a 1/2 and use the identity sin2x

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2sin x cos x = (sin 2x) /2 then we have formula for sin A cos B

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361090244648:dw

sami21
 one year ago
Best ResponseYou've already chosen the best response.0for the first question by parts can also be used . \[\Large \frac{1}{5}\sin^2(x)\sin(5x)\frac{2}{5}\int\limits \sin(x)\sin(5x)\cos(x)dx\]

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0\[( \sin A ) ( \sin B )=\frac{1}{2} (\cos (A B )\cos (A +B ))\]

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0But there's still a lot of work if you do this

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361090429038:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361090501054:dw

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2why  *minus* in between ?

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1integral of sin is cosx

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2both of  from that you have factored out, right ? to make 1/4 ?

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1well, before i took integral

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1dw:1361090806081:dw

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1those will both be negative right?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.2integral of those will be negative, yes, right.

dfresenius
 one year ago
Best ResponseYou've already chosen the best response.1ok thats all i got, thank you so much both of you for helping me out, big test this friday
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