## lirffej Group Title A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help.. one year ago one year ago

1. ParthKohli Group Title

You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

2. ArTFis Group Title

5! = 5 x 4 x 3 x 2 x 1 = 120 ways

3. ParthKohli Group Title

And the number of ways in which they can sit alternately is $$3 \times 2 \times 2 \times 1 \times 1$$

4. laici46le Group Title

3x2x2x1x1

5. lirffej Group Title

6. ParthKohli Group Title

Number of ways they can sit alternately divided by the total number of ways.

7. ArTFis Group Title

@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

8. lirffej Group Title

thank you..

9. lirffej Group Title

3!2! divided by 5!??is that correct??

10. laici46le Group Title

24

11. ParthKohli Group Title

yes, that is right.

12. laici46le Group Title

3C1x2C1x2C1=12...i think its 12...

13. ParthKohli Group Title

yes.

14. ParthKohli Group Title

12/120 = ...

15. laici46le Group Title

1/10

16. ParthKohli Group Title

Yeah!