lirffej
A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..



This Question is Closed

ParthKohli
Best Response
You've already chosen the best response.
0
You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

ArTFis
Best Response
You've already chosen the best response.
0
5! = 5 x 4 x 3 x 2 x 1
= 120 ways

ParthKohli
Best Response
You've already chosen the best response.
0
And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)

laici46le
Best Response
You've already chosen the best response.
0
3x2x2x1x1

lirffej
Best Response
You've already chosen the best response.
0
so??what is the answer?

ParthKohli
Best Response
You've already chosen the best response.
0
Number of ways they can sit alternately divided by the total number of ways.

ArTFis
Best Response
You've already chosen the best response.
0
@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

lirffej
Best Response
You've already chosen the best response.
0
thank you..

lirffej
Best Response
You've already chosen the best response.
0
3!2! divided by 5!??is that correct??

laici46le
Best Response
You've already chosen the best response.
0
24

ParthKohli
Best Response
You've already chosen the best response.
0
yes, that is right.

laici46le
Best Response
You've already chosen the best response.
0
3C1x2C1x2C1=12...i think its 12...

ParthKohli
Best Response
You've already chosen the best response.
0
yes.

ParthKohli
Best Response
You've already chosen the best response.
0
12/120 = ...

laici46le
Best Response
You've already chosen the best response.
0
1/10

ParthKohli
Best Response
You've already chosen the best response.
0
Yeah!