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lirffej

  • 3 years ago

A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..

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  1. ParthKohli
    • 3 years ago
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    You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

  2. ArTFis
    • 3 years ago
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    5! = 5 x 4 x 3 x 2 x 1 = 120 ways

  3. ParthKohli
    • 3 years ago
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    And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)

  4. laici46le
    • 3 years ago
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    3x2x2x1x1

  5. lirffej
    • 3 years ago
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    so??what is the answer?

  6. ParthKohli
    • 3 years ago
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    Number of ways they can sit alternately divided by the total number of ways.

  7. ArTFis
    • 3 years ago
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    @ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

  8. lirffej
    • 3 years ago
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    thank you..

  9. lirffej
    • 3 years ago
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    3!2! divided by 5!??is that correct??

  10. laici46le
    • 3 years ago
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    24

  11. ParthKohli
    • 3 years ago
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    yes, that is right.

  12. laici46le
    • 3 years ago
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    3C1x2C1x2C1=12...i think its 12...

  13. ParthKohli
    • 3 years ago
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    yes.

  14. ParthKohli
    • 3 years ago
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    12/120 = ...

  15. laici46le
    • 3 years ago
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    1/10

  16. ParthKohli
    • 3 years ago
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    Yeah!

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