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lirffej Group Title

A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..

  • one year ago
  • one year ago

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  1. ParthKohli Group Title
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    You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

    • one year ago
  2. ArTFis Group Title
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    5! = 5 x 4 x 3 x 2 x 1 = 120 ways

    • one year ago
  3. ParthKohli Group Title
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    And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)

    • one year ago
  4. laici46le Group Title
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    3x2x2x1x1

    • one year ago
  5. lirffej Group Title
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    so??what is the answer?

    • one year ago
  6. ParthKohli Group Title
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    Number of ways they can sit alternately divided by the total number of ways.

    • one year ago
  7. ArTFis Group Title
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    @ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

    • one year ago
  8. lirffej Group Title
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    thank you..

    • one year ago
  9. lirffej Group Title
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    3!2! divided by 5!??is that correct??

    • one year ago
  10. laici46le Group Title
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    24

    • one year ago
  11. ParthKohli Group Title
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    yes, that is right.

    • one year ago
  12. laici46le Group Title
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    3C1x2C1x2C1=12...i think its 12...

    • one year ago
  13. ParthKohli Group Title
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    yes.

    • one year ago
  14. ParthKohli Group Title
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    12/120 = ...

    • one year ago
  15. laici46le Group Title
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    1/10

    • one year ago
  16. ParthKohli Group Title
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    Yeah!

    • one year ago
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