anonymous
  • anonymous
A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..
Probability
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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ParthKohli
  • ParthKohli
You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.
ArTFis
  • ArTFis
5! = 5 x 4 x 3 x 2 x 1 = 120 ways
ParthKohli
  • ParthKohli
And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)

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More answers

anonymous
  • anonymous
3x2x2x1x1
anonymous
  • anonymous
so??what is the answer?
ParthKohli
  • ParthKohli
Number of ways they can sit alternately divided by the total number of ways.
ArTFis
  • ArTFis
@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.
anonymous
  • anonymous
thank you..
anonymous
  • anonymous
3!2! divided by 5!??is that correct??
anonymous
  • anonymous
24
ParthKohli
  • ParthKohli
yes, that is right.
anonymous
  • anonymous
3C1x2C1x2C1=12...i think its 12...
ParthKohli
  • ParthKohli
yes.
ParthKohli
  • ParthKohli
12/120 = ...
anonymous
  • anonymous
1/10
ParthKohli
  • ParthKohli
Yeah!

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