## anonymous 3 years ago A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..

1. ParthKohli

You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

2. ArTFis

5! = 5 x 4 x 3 x 2 x 1 = 120 ways

3. ParthKohli

And the number of ways in which they can sit alternately is $$3 \times 2 \times 2 \times 1 \times 1$$

4. anonymous

3x2x2x1x1

5. anonymous

6. ParthKohli

Number of ways they can sit alternately divided by the total number of ways.

7. ArTFis

@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

8. anonymous

thank you..

9. anonymous

3!2! divided by 5!??is that correct??

10. anonymous

24

11. ParthKohli

yes, that is right.

12. anonymous

3C1x2C1x2C1=12...i think its 12...

13. ParthKohli

yes.

14. ParthKohli

12/120 = ...

15. anonymous

1/10

16. ParthKohli

Yeah!