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A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..
 one year ago
 one year ago
A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.0
You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.
 one year ago

ArTFisBest ResponseYou've already chosen the best response.0
5! = 5 x 4 x 3 x 2 x 1 = 120 ways
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)
 one year ago

lirffejBest ResponseYou've already chosen the best response.0
so??what is the answer?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Number of ways they can sit alternately divided by the total number of ways.
 one year ago

ArTFisBest ResponseYou've already chosen the best response.0
@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.
 one year ago

lirffejBest ResponseYou've already chosen the best response.0
3!2! divided by 5!??is that correct??
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
yes, that is right.
 one year ago

laici46leBest ResponseYou've already chosen the best response.0
3C1x2C1x2C1=12...i think its 12...
 one year ago
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