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ranxu6j3

i'll use the tool excuse me,

  • one year ago
  • one year ago

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  1. ranxu6j3
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    a and b are vectors, a=(x1,y1) b=(x2,y2) \[\left| a \right|\left| b \right|=\left| adotb \right| \] then why x1y2-x2y1=0 ? please help me

    • one year ago
  2. ranxu6j3
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    plus they are not 0 vectors

    • one year ago
  3. hartnn
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    have you tried this ? its just algebraic manipulations....

    • one year ago
  4. hartnn
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    if you know \( |a|= \sqrt{x_1^2+y_1^2}\) \( |b|= \sqrt{x_2^2+y_2^2}\) \(|a.b|=x_1x_2+y_1y_2\)

    • one year ago
  5. hartnn
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    substitute these and square both sides, what you get ?

    • one year ago
  6. hartnn
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    i see, since you have disappeared offline, i'll write down few steps. \((x_1^2+y_1^2)(x_2^2+y_2^2)= (x_1x_2+y_1y_2)^2\) Expand both sides, and you'll see \(x_1^2x_2^2+y_1^2y_2^2\) gets cancelled from both sides, what remains will give you \((x_1y_2-x_2y_1)^2=0\) which gives you required result.

    • one year ago
  7. ranxu6j3
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    thank you, @hartnn and sorry for disappearing i was using wrong aspects, which made me go nowhere. thanks again

    • one year ago
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