A community for students.
Here's the question you clicked on:
 0 viewing
ranxu6j3
 2 years ago
i'll use the tool
excuse me,
ranxu6j3
 2 years ago
i'll use the tool excuse me,

This Question is Closed

ranxu6j3
 2 years ago
Best ResponseYou've already chosen the best response.0a and b are vectors, a=(x1,y1) b=(x2,y2) \[\left a \right\left b \right=\left adotb \right \] then why x1y2x2y1=0 ? please help me

ranxu6j3
 2 years ago
Best ResponseYou've already chosen the best response.0plus they are not 0 vectors

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2have you tried this ? its just algebraic manipulations....

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2if you know \( a= \sqrt{x_1^2+y_1^2}\) \( b= \sqrt{x_2^2+y_2^2}\) \(a.b=x_1x_2+y_1y_2\)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2substitute these and square both sides, what you get ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.2i see, since you have disappeared offline, i'll write down few steps. \((x_1^2+y_1^2)(x_2^2+y_2^2)= (x_1x_2+y_1y_2)^2\) Expand both sides, and you'll see \(x_1^2x_2^2+y_1^2y_2^2\) gets cancelled from both sides, what remains will give you \((x_1y_2x_2y_1)^2=0\) which gives you required result.

ranxu6j3
 2 years ago
Best ResponseYou've already chosen the best response.0thank you, @hartnn and sorry for disappearing i was using wrong aspects, which made me go nowhere. thanks again
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.