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anonymous
 3 years ago
i'll use the tool
excuse me,
anonymous
 3 years ago
i'll use the tool excuse me,

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0a and b are vectors, a=(x1,y1) b=(x2,y2) \[\left a \right\left b \right=\left adotb \right \] then why x1y2x2y1=0 ? please help me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0plus they are not 0 vectors

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2have you tried this ? its just algebraic manipulations....

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2if you know \( a= \sqrt{x_1^2+y_1^2}\) \( b= \sqrt{x_2^2+y_2^2}\) \(a.b=x_1x_2+y_1y_2\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2substitute these and square both sides, what you get ?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.2i see, since you have disappeared offline, i'll write down few steps. \((x_1^2+y_1^2)(x_2^2+y_2^2)= (x_1x_2+y_1y_2)^2\) Expand both sides, and you'll see \(x_1^2x_2^2+y_1^2y_2^2\) gets cancelled from both sides, what remains will give you \((x_1y_2x_2y_1)^2=0\) which gives you required result.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you, @hartnn and sorry for disappearing i was using wrong aspects, which made me go nowhere. thanks again
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