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a box contains 5 red balls,3 green balls and 4 blue balls. if two balls are drawn in succession without replacement.what is the probability that both are red?..help plzz..

Probability
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5/12x4/11
There are 5 + 3 + 4 = 12 balls in the box. Of these, 5 are red. Probability is the number of desirable outcomes divided by the number of possible outcomes. So, the probability of getting a red ball on the first draw is 5/12.
5/33 should be the answer

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Other answers:

The drawing is done without replacement. Assuming that a red ball was selected on the first draw, then there are now 4 red balls in the box. Also, there are now 11 total balls in the box. The probability of getting a red ball on the second draw is 4/11. The event for which we want the probability is the drawing of two red balls in succession. Therefore, that probability is 5/12 * 4/11 = 20/132 = 5/33. --> If you conduct this drawing of two red balls 33 different times, you can expect to get Red-Red, on average, 5 of the 33 times.
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