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kaiz122

  • one year ago

Directional Derivative please

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  1. kaiz122
    • one year ago
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    \[f(x,y)= \sin(xy)\] at \[2,\frac{\pi}{4}\]

  2. muhammad9t5
    • one year ago
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    do you mean f(x)=sinx. f(y)=siny

  3. kaiz122
    • one year ago
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    no, f(x,y)= sin(xy) Find \[d_{\theta}f(2, \frac{\pi}{4})\]

  4. terenzreignz
    • one year ago
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    Okay, easiest way to do this is with gradients.

  5. muhammad9t5
    • one year ago
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    oh looks like composite function.

  6. kaiz122
    • one year ago
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    my answer is 0. is this right?

  7. terenzreignz
    • one year ago
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    Hang on...

  8. terenzreignz
    • one year ago
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    Sorry, was preoccupied. The directional derivative of a function in the direction of the vector v is given by this formula: \[\large \nabla f(x,y) \cdot \frac{v}{||v||}\]

  9. terenzreignz
    • one year ago
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    So, first, you need to get the unit vector of \[<2, \frac{\pi}{4}>\]

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