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Challenge: When @lgbasallote left OpenStudy, he left us with 44 theoretical dollars. Nine users fight over the money. Lord @shadowfiend decides that all the people will get a distinct amount of money based on a lottery and it must be a natural number. In how many ways can we distribute this money amongst these 9 users?

Mathematics
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a+b+c+d+e+f+g+h+i=44 where a,b,c,d,e,f,g,h,i are distinct whole numbers
we need to find No. of solutions?
Yesh.

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Other answers:

0
Nailed it: I couldn't think of a better problem. -_-
And why?
Minimum sum of nine distinct whole number =45
Wow, perfect.
It was so easy that even my teacup said "zero, you dumbo!"
Easier than it seemed at first... 1+2+3+4...+9 = $45
no i think if we are seeing whole no.s we should include a zero
am i right or wrong someone plz tell.
plz @ParthKohli replyy
W H Y????????????
Fixed, sorry
i did'nt follow it plz explain the previous comment
Oh sorry I should have said natural numbers
because all the people gets distinct amount of money
ok i got it in the question there is natural numbers sorry ............at last
Another question If 0 was included then how many ways?
Then we actually have 8 people to give money to in natural numbers :-D 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36 So there are some ways.
0+2+3+4+5+6+7+8+9=44 So, 9! ways
Yeah.
no in this case i think it can also be 0+1+2+3+4+5+6+7+16 we have to work out a hectic solution
am i right
but still a salute to your knowledge u people are too knowledgeous
u r very correct
i just mentioned 1 possibility it wud be kind enough if u two plz work out the solution and frankly speaking i don't so much calculations thanks
0+2+3+4+5+6+7+8+9 0+1+3+4+5+6+7+8+10 0+1+2+4+5+6+7+8+11 0+1+2+3+5+6+7+8+12 0+1+2+3+4+6+7+8+13 0+1+2+3+4+5+7+8+14 0+1+2+3+4+5+6+8+15 0+1+2+3+4+5+6+7+16 So, 8*9!

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