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JOYAL

  • 2 years ago

if 4 digit numbers greater than 5000 are randomly formed from the digits 1,3,5,7&0,what is the probability of forming a number divisible by 5 when, 1.the digits are repeated? 2.the repetition of digits is not allowed?

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  1. sauravshakya
    • 2 years ago
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    Isnt it 2/5

  2. sauravshakya
    • 2 years ago
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    for 1st case

  3. JOYAL
    • 2 years ago
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    yes... please explain the steps...

  4. sauravshakya
    • 2 years ago
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    To be divisible by 5 the last digit must be either 0 or 5

  5. sauravshakya
    • 2 years ago
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    So, 2/number of different digits we can choose for the last digit = 2/5

  6. JOYAL
    • 2 years ago
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    so,what's the answer for 2 case??????????????

  7. sauravshakya
    • 2 years ago
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    (1*1*3*2 + 1*2*3*2)/(2*4*3*2)

  8. sauravshakya
    • 2 years ago
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    3/8

  9. JOYAL
    • 2 years ago
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    how did you get that !!!

  10. sauravshakya
    • 2 years ago
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    If the first digit is 5 then the last digit must be 0 If the first digit is 7 then the last digit can be either 0 or 5

  11. sauravshakya
    • 2 years ago
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    Which gives No. of numbers divisible by 5 greater than 5000 = 1*1*3*2+1*2*3*2

  12. sauravshakya
    • 2 years ago
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    And No. of numbers that can be formed greater than 5000= 2*4*3*2 as the first digit must be either 5 or 7

  13. sauravshakya
    • 2 years ago
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    got it?

  14. JOYAL
    • 2 years ago
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    yes.thanks.... can you answer 1 more question please?

  15. sauravshakya
    • 2 years ago
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    Okay.... but post it seperately

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