anonymous
  • anonymous
if 4 digit numbers greater than 5000 are randomly formed from the digits 1,3,5,7&0,what is the probability of forming a number divisible by 5 when, 1.the digits are repeated? 2.the repetition of digits is not allowed?
Probability
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Isnt it 2/5
anonymous
  • anonymous
for 1st case
anonymous
  • anonymous
yes... please explain the steps...

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anonymous
  • anonymous
To be divisible by 5 the last digit must be either 0 or 5
anonymous
  • anonymous
So, 2/number of different digits we can choose for the last digit = 2/5
anonymous
  • anonymous
so,what's the answer for 2 case??????????????
anonymous
  • anonymous
(1*1*3*2 + 1*2*3*2)/(2*4*3*2)
anonymous
  • anonymous
3/8
anonymous
  • anonymous
how did you get that !!!
anonymous
  • anonymous
If the first digit is 5 then the last digit must be 0 If the first digit is 7 then the last digit can be either 0 or 5
anonymous
  • anonymous
Which gives No. of numbers divisible by 5 greater than 5000 = 1*1*3*2+1*2*3*2
anonymous
  • anonymous
And No. of numbers that can be formed greater than 5000= 2*4*3*2 as the first digit must be either 5 or 7
anonymous
  • anonymous
got it?
anonymous
  • anonymous
yes.thanks.... can you answer 1 more question please?
anonymous
  • anonymous
Okay.... but post it seperately

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