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\[1-\frac{ 694 }{ 896 }\] do you mean?

No, its P

then p4 do you mean its power or 4 is multiplied?

like p4 or \[p^4\]

I have no idea... It just says 6P4,

Noo, its not that, I'll take a screenshot

ok... i am waiting for screenshot.

This is the problem,

this is Permutation.

ohh..its permutation!

& whats permutation? O_O
I have never ever heard of that

\(!\)
means a factorial.

\(n!= n(n-1)(n-2).......3.2.1\)
when n is a whole number.
like for example
5! = 5*4*3*2*1 = 120

answer is 1 it means that you need to expand 6 as 4 times and 8 as 6 times.

1/56

before getting to permutation, you should know what a factorial ! is .

OH.! so I had something like 10! I would have to do 10*9*8*7*6*5*4*3*2*1= etc..?

yes, thats correct.

6P4= 6*5*4*3
and
8P6= 8*7*6*5*4*3

yes you are correct.

do you want to know how to get that^ ?

yes.

\(\huge ^nP_r = \dfrac{n!}{(n-r)!}\)

So basically I had to do the factorial (!) to the 6P & 8P?

yes.

Everything on the left side of the = is confusing to me

Ah, it does now.! :-)
Thanks you guys both for explaining this to me.!

Thank me when you get to correct answer.

What do you mean?

i meant to ask you, whether you could now figure out the answer of that question...

I do the factorial, 8*7*6*5*4*3*2*1, I thought?

& then divide my answer by 2?

thats for 8P2

Then I'm lost again,

i never said you are wrong. its just not the final answer.

Then I do the same with the 6

6P4 = 6*5*4*3
8P2= 8*7*6*5*4*3
Question asks, 1- 6P4/8P2 = 1- 6*5 / 8*7*6*5 = 1- 1/(8*7)
ok ?

Ah, I wasnt paying attention to the 1,

Would I have to subtract the 1 from the 6 & start factoring 5?

Thats confusing

ok, clear till this :
6P4 = 6*5*4*3
8P2= 8*7*6*5*4*3

Got that...

now divide them
6P4/8P2 =.... ?

I got 0.0178 etc...
Thats not right..

keep it in fractions..

I got 360 from 6*5*4*3 & 20160 from the factorial of 8.

How would I keep it in fractions?

you can also cancel out like this :
|dw:1361120576575:dw|
got that ?

Ah, got it.! I wasnt thinking about canceling out

ask if any more doubts.

What happened to the 4 & 2?

i just realized i mistyped 8P6 (and have written 8P2 instead)
4 and 2 where ?

The 4 after the P and the 2 after the other P

oh, we used the formula, right ?
6-4 = 2, so 2! in the denominator
8-6= 2, so 2! in the denominator

OH.! Ok I get it.!

1/56 wasnt correct, could it be 55/56 by any chance?

?? you forgot '1-...' again ?
1- 1/(7*8)= 1-1/56=(56-1)/56 = 55/56

*face palm*
Thank you.

welcome ^_^