Derive y= (3x-9)^9(x+2)^6 I get y1= 162(3x-9)^8(x+2)^5?

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Derive y= (3x-9)^9(x+2)^6 I get y1= 162(3x-9)^8(x+2)^5?

Mathematics
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The answer is 45x(3x-9)^8(x+2)^5...I don't get it!
you must use the product rule combined with using the chain rule when you find each derivative.
Yep that's what I did! Should I show you my steps?

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Other answers:

yes please, let me take a look
y = (3x-9)^9(x+2)^6 y1 = 9(3)(3x-8)^8 (6)(1)(x+2)^5 y1 = 162 (3x-9)^8(x+2)^5
Thank you
Have I gone wrong somewhere?
yes you forgot to put an addition sign. the product formula is a*d/dx(b) + d/dx(a) * b
OHHHHHHH
when you take the d/dx of the a and the b terms, that's when you execute the sign rule. this is an annoying question lol it will take some time to compute it all
Thank you!!!!!
no problem!

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