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DeadShot

  • 3 years ago

If f(x) = x plus 2, all over 2, then what is f^-1(x) ?

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  1. kropot72
    • 3 years ago
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    \[y=\frac{x+2}{2}\] The next step is to interchange x and y. Do you want me to take you thru it?

  2. agradecompetent
    • 3 years ago
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    2(x-1)

  3. agradecompetent
    • 3 years ago
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    =2(x-1)

  4. DeadShot
    • 3 years ago
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    yes, i don't understand this kind of problem

  5. agradecompetent
    • 3 years ago
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    okay let's do it step by step

  6. kropot72
    • 3 years ago
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    When we interchange x and y we get \[x=\frac{y+2}{2}\] Now we need to solve for y by multiplying both sides by 2 giving\[2x=y+2\] Now you can subtract 2 from both sides to find y which is \[f ^{-1}(x)\]

  7. DeadShot
    • 3 years ago
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    so then, it would be 2x - 2 = y, right?

  8. kropot72
    • 3 years ago
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    @DeadShot Good work. Youare correct. You can factorise 2x - 2 = 2(x - 1)

  9. agradecompetent
    • 3 years ago
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    f(x) = (x+2)/2 =>y=(x+2)/2 2y= x+2 x=2y-2 x=2(y-1) find f^-1(x) f^-1(x) = 2(x-1)

  10. DeadShot
    • 3 years ago
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    Thanks!

  11. kropot72
    • 3 years ago
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    You're welcome :)

  12. agradecompetent
    • 3 years ago
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    you are welcome Deadshot

  13. Pibe
    • 2 years ago
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    so is it 2x-2 or 2x-1?

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