DeadShot
If f(x) = x plus 2, all over 2, then what is f^-1(x) ?
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kropot72
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\[y=\frac{x+2}{2}\]
The next step is to interchange x and y. Do you want me to take you thru it?
agradecompetent
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2(x-1)
agradecompetent
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=2(x-1)
DeadShot
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yes, i don't understand this kind of problem
agradecompetent
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okay let's do it step by step
kropot72
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When we interchange x and y we get
\[x=\frac{y+2}{2}\]
Now we need to solve for y by multiplying both sides by 2 giving\[2x=y+2\]
Now you can subtract 2 from both sides to find y which is
\[f ^{-1}(x)\]
DeadShot
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so then, it would be 2x - 2 = y, right?
kropot72
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@DeadShot Good work. Youare correct. You can factorise 2x - 2 = 2(x - 1)
agradecompetent
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f(x) = (x+2)/2
=>y=(x+2)/2
2y= x+2
x=2y-2
x=2(y-1)
find f^-1(x)
f^-1(x) = 2(x-1)
DeadShot
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Thanks!
kropot72
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You're welcome :)
agradecompetent
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you are welcome Deadshot
Pibe
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so is it 2x-2 or 2x-1?