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gjhfdfgBest ResponseYou've already chosen the best response.0
dw:1361134701384:dw Would it be  infinity 6?
 one year ago

zenaiBest ResponseYou've already chosen the best response.0
okay for square roots you have a limiting situation. You cannot take a square root of a negative number. So when this equation equals a number below zero, it will not work. Therefore your domain would equal \[[6, \infty)\] because at x=6 it would be the square root of zero which is zero, however at anything lower it would be the square root of a negative number which cannot exist.
 one year ago

gjhfdfgBest ResponseYou've already chosen the best response.0
Wouldnt the infinity be negative though?
 one year ago

zenaiBest ResponseYou've already chosen the best response.0
no, the infinity must be positive. Negative infinity means every number less than zero, your equation cannot have anything less than 6, and since negative infinity includes 7, 8, 9, etc it cannot be the answer.
 one year ago

gjhfdfgBest ResponseYou've already chosen the best response.0
I don't have a just 6 & positive infinity answer, thats why its throwing me off
 one year ago

zenaiBest ResponseYou've already chosen the best response.0
hmmmmm, can you take a picture or type the rest of the answers?
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
Solve the inequality that represents the problem. You want all values of x that make the radicand nonnegative. 6  x >= 0 x >= 6 x <= 6
 one year ago

zenaiBest ResponseYou've already chosen the best response.0
oh, I'm retarded, if its a NEGATIVE number the value is valid, if x = 7 for example, then the equation becomes wrong, you were right it is (negative inf, 6] sorry!
 one year ago

gjhfdfgBest ResponseYou've already chosen the best response.0
Haha, no problem. It happens. :P But thanks anyways.!
 one year ago
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