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|dw:1361134701384:dw| Would it be - infinity 6?
okay for square roots you have a limiting situation. You cannot take a square root of a negative number. So when this equation equals a number below zero, it will not work. Therefore your domain would equal \[[6, \infty)\] because at x=6 it would be the square root of zero which is zero, however at anything lower it would be the square root of a negative number which cannot exist.
Wouldnt the infinity be negative though?

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no, the infinity must be positive. Negative infinity means every number less than zero, your equation cannot have anything less than 6, and since negative infinity includes -7, -8, -9, etc it cannot be the answer.
I don't have a just 6 & positive infinity answer, thats why its throwing me off
hmmmmm, can you take a picture or type the rest of the answers?
Solve the inequality that represents the problem. You want all values of x that make the radicand non-negative. 6 - x >= 0 -x >= -6 x <= 6
oh, I'm retarded, if its a NEGATIVE number the value is valid, if x = 7 for example, then the equation becomes wrong, you were right it is (negative inf, 6] sorry!
(-infinity, 6]
Haha, no problem. It happens. :P But thanks anyways.!

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