## gjhfdfg Group Title Find the domain, one year ago one year ago

1. gjhfdfg Group Title

|dw:1361134701384:dw| Would it be - infinity 6?

2. zenai Group Title

okay for square roots you have a limiting situation. You cannot take a square root of a negative number. So when this equation equals a number below zero, it will not work. Therefore your domain would equal $[6, \infty)$ because at x=6 it would be the square root of zero which is zero, however at anything lower it would be the square root of a negative number which cannot exist.

3. gjhfdfg Group Title

Wouldnt the infinity be negative though?

4. zenai Group Title

no, the infinity must be positive. Negative infinity means every number less than zero, your equation cannot have anything less than 6, and since negative infinity includes -7, -8, -9, etc it cannot be the answer.

5. gjhfdfg Group Title

I don't have a just 6 & positive infinity answer, thats why its throwing me off

6. zenai Group Title

hmmmmm, can you take a picture or type the rest of the answers?

7. mathstudent55 Group Title

Solve the inequality that represents the problem. You want all values of x that make the radicand non-negative. 6 - x >= 0 -x >= -6 x <= 6

8. zenai Group Title

oh, I'm retarded, if its a NEGATIVE number the value is valid, if x = 7 for example, then the equation becomes wrong, you were right it is (negative inf, 6] sorry!

9. mathstudent55 Group Title

(-infinity, 6]

10. gjhfdfg Group Title

Haha, no problem. It happens. :P But thanks anyways.!