At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
|dw:1361134701384:dw| Would it be - infinity 6?
okay for square roots you have a limiting situation. You cannot take a square root of a negative number. So when this equation equals a number below zero, it will not work. Therefore your domain would equal \[[6, \infty)\] because at x=6 it would be the square root of zero which is zero, however at anything lower it would be the square root of a negative number which cannot exist.
Wouldnt the infinity be negative though?
no, the infinity must be positive. Negative infinity means every number less than zero, your equation cannot have anything less than 6, and since negative infinity includes -7, -8, -9, etc it cannot be the answer.
I don't have a just 6 & positive infinity answer, thats why its throwing me off
hmmmmm, can you take a picture or type the rest of the answers?
Solve the inequality that represents the problem. You want all values of x that make the radicand non-negative. 6 - x >= 0 -x >= -6 x <= 6
oh, I'm retarded, if its a NEGATIVE number the value is valid, if x = 7 for example, then the equation becomes wrong, you were right it is (negative inf, 6] sorry!
Haha, no problem. It happens. :P But thanks anyways.!