## gjhfdfg 2 years ago Find the domain,

1. gjhfdfg

|dw:1361134701384:dw| Would it be - infinity 6?

2. zenai

okay for square roots you have a limiting situation. You cannot take a square root of a negative number. So when this equation equals a number below zero, it will not work. Therefore your domain would equal $[6, \infty)$ because at x=6 it would be the square root of zero which is zero, however at anything lower it would be the square root of a negative number which cannot exist.

3. gjhfdfg

Wouldnt the infinity be negative though?

4. zenai

no, the infinity must be positive. Negative infinity means every number less than zero, your equation cannot have anything less than 6, and since negative infinity includes -7, -8, -9, etc it cannot be the answer.

5. gjhfdfg

I don't have a just 6 & positive infinity answer, thats why its throwing me off

6. zenai

hmmmmm, can you take a picture or type the rest of the answers?

7. mathstudent55

Solve the inequality that represents the problem. You want all values of x that make the radicand non-negative. 6 - x >= 0 -x >= -6 x <= 6

8. zenai

oh, I'm retarded, if its a NEGATIVE number the value is valid, if x = 7 for example, then the equation becomes wrong, you were right it is (negative inf, 6] sorry!

9. mathstudent55

(-infinity, 6]

10. gjhfdfg

Haha, no problem. It happens. :P But thanks anyways.!