gjhfdfg
Finding inverses to the one-to-one functions,
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gjhfdfg
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This is what I'm working on,
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gjhfdfg
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I thought it was 7/2x-5 but I was wrong
poopsiedoodle
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-7/-2x-5? just a guess. I'm not sure.
gjhfdfg
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There arent any -7's in it
poopsiedoodle
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well I know, but -7 is the opposite of 7. There aren't any -5s in it either. That looks like a +5 up there.
gjhfdfg
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Hmm
gjhfdfg
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I don't think it necessarily wants the opposite of everything
zenai
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switch x and y and solve for y for the inverse of a function. \[x = \frac{ 2y+5 }{ 7}\]
Meepi
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\[y = \frac{2x + 5}{7}\]
To get the inverse, solve for x, then swap x and y
\[y = \frac{2x + 5}{7}\]
\[7y - 5 = 2x\]
\[x = \frac{7y - 5}{2}\]
So the inverse function is
\[f^{-1}(x) = \frac{7x - 5}{2}\]
zenai
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^ he's right :P
gjhfdfg
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Got it thanks. ^^