anonymous
  • anonymous
Finding inverses to the one-to-one functions,
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
This is what I'm working on, |dw:1361136194386:dw|
anonymous
  • anonymous
I thought it was 7/2x-5 but I was wrong
poopsiedoodle
  • poopsiedoodle
-7/-2x-5? just a guess. I'm not sure.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
There arent any -7's in it
poopsiedoodle
  • poopsiedoodle
well I know, but -7 is the opposite of 7. There aren't any -5s in it either. That looks like a +5 up there.
anonymous
  • anonymous
Hmm
anonymous
  • anonymous
I don't think it necessarily wants the opposite of everything
anonymous
  • anonymous
switch x and y and solve for y for the inverse of a function. \[x = \frac{ 2y+5 }{ 7}\]
anonymous
  • anonymous
\[y = \frac{2x + 5}{7}\] To get the inverse, solve for x, then swap x and y \[y = \frac{2x + 5}{7}\] \[7y - 5 = 2x\] \[x = \frac{7y - 5}{2}\] So the inverse function is \[f^{-1}(x) = \frac{7x - 5}{2}\]
anonymous
  • anonymous
^ he's right :P
anonymous
  • anonymous
Got it thanks. ^^

Looking for something else?

Not the answer you are looking for? Search for more explanations.