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Finding inverses to the one-to-one functions,

Mathematics
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This is what I'm working on, |dw:1361136194386:dw|
I thought it was 7/2x-5 but I was wrong
-7/-2x-5? just a guess. I'm not sure.

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Other answers:

There arent any -7's in it
well I know, but -7 is the opposite of 7. There aren't any -5s in it either. That looks like a +5 up there.
Hmm
I don't think it necessarily wants the opposite of everything
switch x and y and solve for y for the inverse of a function. \[x = \frac{ 2y+5 }{ 7}\]
\[y = \frac{2x + 5}{7}\] To get the inverse, solve for x, then swap x and y \[y = \frac{2x + 5}{7}\] \[7y - 5 = 2x\] \[x = \frac{7y - 5}{2}\] So the inverse function is \[f^{-1}(x) = \frac{7x - 5}{2}\]
^ he's right :P
Got it thanks. ^^

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