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jumpda

try to understand long division

  • one year ago
  • one year ago

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  1. precal
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    |dw:1361139136058:dw|

    • one year ago
  2. precal
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    |dw:1361139152210:dw|

    • one year ago
  3. precal
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    |dw:1361139188639:dw|

    • one year ago
  4. precal
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    |dw:1361139201853:dw|

    • one year ago
  5. precal
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    |dw:1361139222616:dw|

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  6. precal
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    |dw:1361139242204:dw|

    • one year ago
  7. precal
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    remainder is 7/(x+2)

    • one year ago
  8. precal
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    hope that helps

    • one year ago
  9. jumpda
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    freshmen in college

    • one year ago
  10. jumpda
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    yea

    • one year ago
  11. jumpda
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    ok how do i do that

    • one year ago
  12. kausarsalley
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    |dw:1362594640625:dw| first of all, since there is no x-term, you would have to create space for it by writing 0x. then,x divides 3x2 and leaves a remainder of 3x which you right at the top on the 0x. the 3x multiplies the x+2.

    • one year ago
  13. kausarsalley
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    you would then subtract the final from the initial. write your final answer and write the next number down beside your result. x divides -6x and leaves a remainder of -6 which you write at the top. the -6 multiplies the x+2 to give you -6x-12 .

    • one year ago
  14. kausarsalley
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    subtract the -6x-12 from -6x+5 and that would be the remainder.

    • one year ago
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