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krissywatts

  • one year ago

help please i need step by step shown: the line passing through (2,b) and (4,6) is parallel to the line joining (1,4) and (-1,7) find b.

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  1. krissywatts
    • one year ago
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    @tomo

  2. tomo
    • one year ago
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    find the slope of each line. set the two sides equal to each other to find b. slope = (y2-y1)/(x2-x1) using (2,b) and (4,6) (x1,y1) = (2,b) (x2,y2) = (4,6) (6-b)/(4-2) (6-b)/2. that is the slope of the line with (2,b) and (4,6) as two points on the line. find the slope of the other line, then post what you get. then we can go from there.

  3. krissywatts
    • one year ago
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    the other is 7-4/-1-1= 3/-2 so what do i need to do from here?

  4. tomo
    • one year ago
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    ok, we know that the two lines are parallel, therefore their slopes are equal. set their slopes equal and solve for b. (6-b)/2 = (3/-2)

  5. krissywatts
    • one year ago
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    what would the 6-b/2 be?

  6. tomo
    • one year ago
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    you want to cross multiply. (6-b)/2 = (3/-2) (6-b)*(-2) = (2*3) -12+2b = 6 2b = 18 b = 9

  7. krissywatts
    • one year ago
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    oh okay i thought i had to multiply as is im sorry. Thanks.

  8. tomo
    • one year ago
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    yw

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