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anonymous
 3 years ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=1/x^4, y=0, x=2, x=6, about y=4
anonymous
 3 years ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y=1/x^4, y=0, x=2, x=6, about y=4

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I would use the method of cylindrical shells. At any f(x) value between 2 and 6, what is the radius from that y point to y = 4?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Which method u prefer? shell or washer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I just need help setting it up to integrate then i can take it from there...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The setup of the integral depends on the method you use....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0^ I didn't see your comment.. the washer method :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Why you choose washersssssss D:

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0isn't easier? or not? usually for me it is easier..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i agree that washer is appropriate here.... hang on....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0You guys have fun with that >_>

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361159214153:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Can you give me the expression for R and r?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no... i don't think it's that.. :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0consider this...dw:1361159501396:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for R, shouldn't it be 1/x^4 + 4 ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0  + .. err yeah my bad

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok... you also agree that r = 4 (inner radius) ???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so... \(\large dV=\pi(R^2r^2)dx \) so \(\large V=\pi \int_2^6(R^2r^2)dx \) you replace the expressions for R and r ....

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry... i gotta leave... :(

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i'm pretty sure what we have is correct....
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