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monroe17
Group Title
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=1/x^4, y=0, x=2, x=6, about y=4
 one year ago
 one year ago
monroe17 Group Title
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y=1/x^4, y=0, x=2, x=6, about y=4
 one year ago
 one year ago

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math>philosophy Group TitleBest ResponseYou've already chosen the best response.0
I would use the method of cylindrical shells. At any f(x) value between 2 and 6, what is the radius from that y point to y = 4?
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
Which method u prefer? shell or washer?
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
I just need help setting it up to integrate then i can take it from there...
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
The setup of the integral depends on the method you use....
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
^ I didn't see your comment.. the washer method :)
 one year ago

math>philosophy Group TitleBest ResponseYou've already chosen the best response.0
Why you choose washersssssss D:
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
isn't easier? or not? usually for me it is easier..
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
i agree that washer is appropriate here.... hang on....
 one year ago

math>philosophy Group TitleBest ResponseYou've already chosen the best response.0
You guys have fun with that >_>
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
dw:1361159214153:dw
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
Can you give me the expression for R and r?
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
errr.. ;/ crap.
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
no... i don't think it's that.. :)
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
haha give me a sec
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
consider this...dw:1361159501396:dw
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
would it be 1/x^44
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
for R, shouldn't it be 1/x^4 + 4 ???
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
  + .. err yeah my bad
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
ok... you also agree that r = 4 (inner radius) ???
 one year ago

monroe17 Group TitleBest ResponseYou've already chosen the best response.0
yupp it is
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
so... \(\large dV=\pi(R^2r^2)dx \) so \(\large V=\pi \int_2^6(R^2r^2)dx \) you replace the expressions for R and r ....
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
sorry... i gotta leave... :(
 one year ago

ByteMe Group TitleBest ResponseYou've already chosen the best response.2
i'm pretty sure what we have is correct....
 one year ago
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