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 one year ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis.
y=1/x^4, y=0, x=2, x=6, about y=4
 one year ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y=1/x^4, y=0, x=2, x=6, about y=4

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math>philosophy
 one year ago
Best ResponseYou've already chosen the best response.0I would use the method of cylindrical shells. At any f(x) value between 2 and 6, what is the radius from that y point to y = 4?

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2Which method u prefer? shell or washer?

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0I just need help setting it up to integrate then i can take it from there...

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2The setup of the integral depends on the method you use....

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0^ I didn't see your comment.. the washer method :)

math>philosophy
 one year ago
Best ResponseYou've already chosen the best response.0Why you choose washersssssss D:

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0isn't easier? or not? usually for me it is easier..

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2i agree that washer is appropriate here.... hang on....

math>philosophy
 one year ago
Best ResponseYou've already chosen the best response.0You guys have fun with that >_>

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2Can you give me the expression for R and r?

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2no... i don't think it's that.. :)

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2consider this...dw:1361159501396:dw

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2for R, shouldn't it be 1/x^4 + 4 ???

monroe17
 one year ago
Best ResponseYou've already chosen the best response.0  + .. err yeah my bad

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2ok... you also agree that r = 4 (inner radius) ???

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2so... \(\large dV=\pi(R^2r^2)dx \) so \(\large V=\pi \int_2^6(R^2r^2)dx \) you replace the expressions for R and r ....

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2sorry... i gotta leave... :(

ByteMe
 one year ago
Best ResponseYou've already chosen the best response.2i'm pretty sure what we have is correct....
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