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Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y=1/x^4, y=0, x=2, x=6, about y=-4

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I would use the method of cylindrical shells. At any f(x) value between 2 and 6, what is the radius from that y point to y = -4?
Which method u prefer? shell or washer?
I just need help setting it up to integrate then i can take it from there...

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Other answers:

The setup of the integral depends on the method you use....
^ I didn't see your comment.. the washer method :)
Why you choose washersssssss D:
isn't easier? or not? usually for me it is easier..
i agree that washer is appropriate here.... hang on....
You guys have fun with that >_>
Can you give me the expression for R and r?
errr.. ;/ crap.
no... i don't think it's that.. :)
haha give me a sec
consider this...|dw:1361159501396:dw|
would it be 1/x^4-4
for R, shouldn't it be 1/x^4 + 4 ???
- - + .. err yeah my bad
ok... you also agree that r = 4 (inner radius) ???
yupp it is
so... \(\large dV=\pi(R^2-r^2)dx \) so \(\large V=\pi \int_2^6(R^2-r^2)dx \) you replace the expressions for R and r ....
sorry... i gotta leave... :(
i'm pretty sure what we have is correct....

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