Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

fukb333

  • 3 years ago

Calculate the mass of CaCO3 required to liberate 10 litres of CO2 at STP

  • This Question is Open
  1. RAJATCHOUDHARY
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    CaCO3 → CaO + CO2 100 22.4 L 22.4 L of CO2 = 100 gm of CaCO3 10.0 L of CO2 = 100 x 10 / 22.4 = 44.64 gm of CaCO3

  2. ranxu6j3
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ps because STP 22.4L=1MOLE

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy