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Calculate the mass of CaCO3 required to liberate 10 litres of CO2 at STP

  • one year ago
  • one year ago

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    CaCO3 → CaO + CO2 100 22.4 L 22.4 L of CO2 = 100 gm of CaCO3 10.0 L of CO2 = 100 x 10 / 22.4 = 44.64 gm of CaCO3

    • one year ago
  2. ranxu6j3
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    ps because STP 22.4L=1MOLE

    • one year ago
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