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where is the function f(c)

c=3, f(x)= (x^2+5)/(x-6)
continuous or no?... is the question.

at c=3, yes... the function is defined at x=3 so the limit of f is f(3)

what if x=c is not defined?

the limit can still exist but not necessarily at f(c)?

oh! so then if x=6 was not an asymptote, but a hole, the limit would be equivalent to f(c)??

***IF*** the function was CONTINUOUS at x=6, then the limit would be f(6)

so...no?

yes!!!! ok, thank you!

yw...:)