Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

is lim as x approaches c the same as f(c)?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
where is the function f(c)
c=3, f(x)= (x^2+5)/(x-6) continuous or no?... is the question.
at c=3, yes... the function is defined at x=3 so the limit of f is f(3)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

what if x=c is not defined?
if f(x) is not defined at x=c, then the limit can still exist but not necessarily at f(c). also, if there is a vertical asymptote at x=c, then the limit does not exist.
the limit can still exist but not necessarily at f(c)?
yes... for example... |dw:1361168628388:dw| here, the limit of f(x) as x approaches c is a.... NOT f(c)
OHHH so then in that case it would be dicontinuous? When can you tell, or what can you do, to know that something is continuous, but algebraically? step by step and explain?
yes... but in your original function, it is continuous at all x values except at x=6. so in your problem, the limit of f as x approaches c for any value OTHER THAN 6, will be f(c)
oh! so then if x=6 was not an asymptote, but a hole, the limit would be equivalent to f(c)??
***IF*** the function was CONTINUOUS at x=6, then the limit would be f(6)
seems like we're going in circles here but we're not... Continuity of a funtion is defined in terms of limits....
so...no?
if the "hole" you're referring to is a REMOVABLE discontinuity, then yes, the limit would be f(6) or as you said, f(c)...
yes!!!! ok, thank you!
yw...:)

Not the answer you are looking for?

Search for more explanations.

Ask your own question