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burhan101Best ResponseYou've already chosen the best response.0
dw:1361169366936:dw
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
I GOT THIS, I JUST ACED A TEST OVER THIS.. ONE SECOND
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
okay, first can you give me what the problem says so i can depict the picture a little better?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
thats the picture given !
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
but here ill rewrite the question
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
A camera is suspended by two wires over a football field to get shots of the action form above. At one point, the camera is closer to the left side of the field. The tension in the wire on the left is 1500 N, and the tension in the wire on the right is 800 N. The angle between the two wires is 130 degrees. Determine the approximate magnitude and direction of the resultant force.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1361220921232:dw
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
That says 50 degrees, i accidentally typed N
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
dw:1361220666415:dw the only thing i dont understand is the 50 degrees you just mentioned.. was that given? how did you get that?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
That is the picture given
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
so the 800N is going directly East and the 1500N is going that 50deg direction?
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
okay so that means to get the component form you put <1500cos50, 1500sin50> and add that with <800, 0> **the sine is zero because it is on the xaxis.** and what do you get?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
Why do you put <1500cos50, 1500sin50>
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
that should give you <1764, 1149> you have to sqaure them and set them equal to the resulant vector so R (being the resultant vector)....dw:1361221683792:dw
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
that is the formula you use in order to put the two vectors in component form. then once you do that, you have to take the square root of the numbers you get squared.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
But its not a right triangle :S
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
you're doing the Pythagorean theorem right
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
it doesnt have to be a right triangle
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
but i was using the distance formula
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
If you dont understand it, i recommend quickly looking over this site (only should take 5 minutes) and then come back and try to see if you understand anything more and if you have any questions i am happy to help! :) http://hotmath.com/hotmath_help/topics/magnitudeanddirectionofvectors.html
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
@ihatealgebrasomuch okay then what do i do with the R i get 2105.207
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
i dont get how you got thoses number from 1500N and 800 N
 one year ago

ihatealgebrasomuchBest ResponseYou've already chosen the best response.1
okay, that is the magnitude of the resultant vector, not all you have to do if find the direction which is tan^1 (sin/cos) or in this case 1149/1764 which ends up being about 33 degrees
 one year ago
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