- anonymous

Determine magnitude and direction of resulting vector

- katieb

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- anonymous

|dw:1361169366936:dw|

- anonymous

I GOT THIS, I JUST ACED A TEST OVER THIS.. ONE SECOND

- anonymous

okay, first can you give me what the problem says so i can depict the picture a little better?

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- anonymous

OKAY :D

- anonymous

thats the picture given !

- anonymous

but here ill rewrite the question

- anonymous

A camera is suspended by two wires over a football field to get shots of the action form above. At one point, the camera is closer to the left side of the field. The tension in the wire on the left is 1500 N, and the tension in the wire on the right is 800 N. The angle between the two wires is 130 degrees. Determine the approximate magnitude and direction of the resultant force.

- anonymous

|dw:1361220921232:dw|

- anonymous

That says 50 degrees, i accidentally typed N

- anonymous

|dw:1361220666415:dw| the only thing i dont understand is the 50 degrees you just mentioned.. was that given? how did you get that?

- anonymous

That is the picture given

- anonymous

so the 800N is going directly East and the 1500N is going that 50deg direction?

- anonymous

Yup !

- anonymous

okay so that means to get the component form you put <1500cos50, 1500sin50> and add that with <800, 0> **the sine is zero because it is on the x-axis.** and what do you get?

- anonymous

Why do you put <1500cos50, 1500sin50>

- anonymous

that should give you <1764, 1149> you have to sqaure them and set them equal to the resulant vector so R (being the resultant vector)....|dw:1361221683792:dw|

- anonymous

that is the formula you use in order to put the two vectors in component form. then once you do that, you have to take the square root of the numbers you get squared.

- anonymous

But its not a right triangle :S

- anonymous

you're doing the Pythagorean theorem right

- anonymous

it doesnt have to be a right triangle

- anonymous

but i was using the distance formula

- anonymous

If you dont understand it, i recommend quickly looking over this site (only should take 5 minutes) and then come back and try to see if you understand anything more and if you have any questions i am happy to help! :) http://hotmath.com/hotmath_help/topics/magnitude-and-direction-of-vectors.html

- anonymous

@ihatealgebrasomuch okay then what do i do with the R i get 2105.207

- anonymous

i dont get it

- anonymous

i dont get how you got thoses number from 1500N and 800 N

- anonymous

okay, that is the magnitude of the resultant vector, not all you have to do if find the direction which is tan^-1 (sin/cos) or in this case 1149/1764 which ends up being about 33 degrees

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