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burhan101 Group Title

Determine magnitude and direction of resulting vector

  • one year ago
  • one year ago

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  1. burhan101 Group Title
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    |dw:1361169366936:dw|

    • one year ago
  2. ihatealgebrasomuch Group Title
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    I GOT THIS, I JUST ACED A TEST OVER THIS.. ONE SECOND

    • one year ago
  3. ihatealgebrasomuch Group Title
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    okay, first can you give me what the problem says so i can depict the picture a little better?

    • one year ago
  4. burhan101 Group Title
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    OKAY :D

    • one year ago
  5. burhan101 Group Title
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    thats the picture given !

    • one year ago
  6. burhan101 Group Title
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    but here ill rewrite the question

    • one year ago
  7. burhan101 Group Title
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    A camera is suspended by two wires over a football field to get shots of the action form above. At one point, the camera is closer to the left side of the field. The tension in the wire on the left is 1500 N, and the tension in the wire on the right is 800 N. The angle between the two wires is 130 degrees. Determine the approximate magnitude and direction of the resultant force.

    • one year ago
  8. burhan101 Group Title
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    |dw:1361220921232:dw|

    • one year ago
  9. burhan101 Group Title
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    That says 50 degrees, i accidentally typed N

    • one year ago
  10. ihatealgebrasomuch Group Title
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    |dw:1361220666415:dw| the only thing i dont understand is the 50 degrees you just mentioned.. was that given? how did you get that?

    • one year ago
  11. burhan101 Group Title
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    That is the picture given

    • one year ago
  12. ihatealgebrasomuch Group Title
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    so the 800N is going directly East and the 1500N is going that 50deg direction?

    • one year ago
  13. burhan101 Group Title
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    Yup !

    • one year ago
  14. ihatealgebrasomuch Group Title
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    okay so that means to get the component form you put <1500cos50, 1500sin50> and add that with <800, 0> **the sine is zero because it is on the x-axis.** and what do you get?

    • one year ago
  15. burhan101 Group Title
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    Why do you put <1500cos50, 1500sin50>

    • one year ago
  16. ihatealgebrasomuch Group Title
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    that should give you <1764, 1149> you have to sqaure them and set them equal to the resulant vector so R (being the resultant vector)....|dw:1361221683792:dw|

    • one year ago
  17. ihatealgebrasomuch Group Title
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    that is the formula you use in order to put the two vectors in component form. then once you do that, you have to take the square root of the numbers you get squared.

    • one year ago
  18. burhan101 Group Title
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    But its not a right triangle :S

    • one year ago
  19. burhan101 Group Title
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    you're doing the Pythagorean theorem right

    • one year ago
  20. ihatealgebrasomuch Group Title
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    it doesnt have to be a right triangle

    • one year ago
  21. ihatealgebrasomuch Group Title
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    but i was using the distance formula

    • one year ago
  22. ihatealgebrasomuch Group Title
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    If you dont understand it, i recommend quickly looking over this site (only should take 5 minutes) and then come back and try to see if you understand anything more and if you have any questions i am happy to help! :) http://hotmath.com/hotmath_help/topics/magnitude-and-direction-of-vectors.html

    • one year ago
  23. burhan101 Group Title
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    @ihatealgebrasomuch okay then what do i do with the R i get 2105.207

    • one year ago
  24. burhan101 Group Title
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    i dont get it

    • one year ago
  25. burhan101 Group Title
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    i dont get how you got thoses number from 1500N and 800 N

    • one year ago
  26. ihatealgebrasomuch Group Title
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    okay, that is the magnitude of the resultant vector, not all you have to do if find the direction which is tan^-1 (sin/cos) or in this case 1149/1764 which ends up being about 33 degrees

    • one year ago
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