Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

burhan101

  • one year ago

Determine magnitude and direction of resulting vector

  • This Question is Closed
  1. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1361169366936:dw|

  2. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I GOT THIS, I JUST ACED A TEST OVER THIS.. ONE SECOND

  3. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, first can you give me what the problem says so i can depict the picture a little better?

  4. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    OKAY :D

  5. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats the picture given !

  6. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but here ill rewrite the question

  7. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    A camera is suspended by two wires over a football field to get shots of the action form above. At one point, the camera is closer to the left side of the field. The tension in the wire on the left is 1500 N, and the tension in the wire on the right is 800 N. The angle between the two wires is 130 degrees. Determine the approximate magnitude and direction of the resultant force.

  8. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1361220921232:dw|

  9. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That says 50 degrees, i accidentally typed N

  10. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1361220666415:dw| the only thing i dont understand is the 50 degrees you just mentioned.. was that given? how did you get that?

  11. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That is the picture given

  12. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so the 800N is going directly East and the 1500N is going that 50deg direction?

  13. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yup !

  14. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    okay so that means to get the component form you put <1500cos50, 1500sin50> and add that with <800, 0> **the sine is zero because it is on the x-axis.** and what do you get?

  15. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Why do you put <1500cos50, 1500sin50>

  16. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that should give you <1764, 1149> you have to sqaure them and set them equal to the resulant vector so R (being the resultant vector)....|dw:1361221683792:dw|

  17. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    that is the formula you use in order to put the two vectors in component form. then once you do that, you have to take the square root of the numbers you get squared.

  18. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    But its not a right triangle :S

  19. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you're doing the Pythagorean theorem right

  20. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    it doesnt have to be a right triangle

  21. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but i was using the distance formula

  22. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    If you dont understand it, i recommend quickly looking over this site (only should take 5 minutes) and then come back and try to see if you understand anything more and if you have any questions i am happy to help! :) http://hotmath.com/hotmath_help/topics/magnitude-and-direction-of-vectors.html

  23. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @ihatealgebrasomuch okay then what do i do with the R i get 2105.207

  24. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont get it

  25. burhan101
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont get how you got thoses number from 1500N and 800 N

  26. ihatealgebrasomuch
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, that is the magnitude of the resultant vector, not all you have to do if find the direction which is tan^-1 (sin/cos) or in this case 1149/1764 which ends up being about 33 degrees

  27. Not the answer you are looking for?
    Search for more explanations.

    Search OpenStudy
    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.