anonymous
  • anonymous
how to re arrange the following as y=mx+c 1. 1/x+5=2/y 2. 3/x=1/y
Mathematics
jamiebookeater
  • jamiebookeater
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whpalmer4
  • whpalmer4
\[\frac1{x + 5} = \frac2y\] Is that correct? You really should either use the Equation editor or parentheses to make the meaning of your equations clear!
campbell_st
  • campbell_st
just cross multiply so the 1st equation becomes \[y = 2(x + 5)\] now just expand and simplify to the equation to be in the form of y = mx + c same process for the 2nd equation.
anonymous
  • anonymous
1st question i understood but second one i just have no idea to solve it as y=mx+b

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whpalmer4
  • whpalmer4
\[\frac3x=\frac1y\]Multiply both sides by \(xy\) and you get \[3y = x\]\[y=\frac x3\]
whpalmer4
  • whpalmer4
which is \[y=(\frac{1}3)x+b\]where \(b=0\)
anonymous
  • anonymous
thanq dear

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