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girleegurl

  • 2 years ago

how to re arrange the following as y=mx+c 1. 1/x+5=2/y 2. 3/x=1/y

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  1. whpalmer4
    • 2 years ago
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    \[\frac1{x + 5} = \frac2y\] Is that correct? You really should either use the Equation editor or parentheses to make the meaning of your equations clear!

  2. campbell_st
    • 2 years ago
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    just cross multiply so the 1st equation becomes \[y = 2(x + 5)\] now just expand and simplify to the equation to be in the form of y = mx + c same process for the 2nd equation.

  3. girleegurl
    • 2 years ago
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    1st question i understood but second one i just have no idea to solve it as y=mx+b

  4. whpalmer4
    • 2 years ago
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    \[\frac3x=\frac1y\]Multiply both sides by \(xy\) and you get \[3y = x\]\[y=\frac x3\]

  5. whpalmer4
    • 2 years ago
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    which is \[y=(\frac{1}3)x+b\]where \(b=0\)

  6. girleegurl
    • 2 years ago
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    thanq dear

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