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1st question i understood but second one i just have no idea to solve it as y=mx+b

\[\frac3x=\frac1y\]Multiply both sides by \(xy\) and you get
\[3y = x\]\[y=\frac x3\]

which is \[y=(\frac{1}3)x+b\]where \(b=0\)

thanq dear