anonymous
  • anonymous
Write the following expression as a function of a positive acute angle. cos 125
Mathematics
jamiebookeater
  • jamiebookeater
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terenzreignz
  • terenzreignz
@aussy123 It might help you to know that with your angle in degrees, \[\large \cos \ \theta = \sin (90^o - \theta) \]
terenzreignz
  • terenzreignz
So \[\large \cos(125^o)=\sin(90^o - 125^o)=\sin(-35^o)\]
anonymous
  • anonymous
why did you use sin

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terenzreignz
  • terenzreignz
It's an identity. It didn't say to use a specific function, it just says use a function.
anonymous
  • anonymous
oh sorry
terenzreignz
  • terenzreignz
Get it now?
anonymous
  • anonymous
yes a little
anonymous
  • anonymous
the answer is -cos55
terenzreignz
  • terenzreignz
I suppose so. You're right :) It stems from the fact that it's equal to sin(-35) = -sin(35) = -cos(90 - 35)
anonymous
  • anonymous
I tried that way too, but I also did cos 125 = cos (180 - 125) = - cos 55
terenzreignz
  • terenzreignz
Well, as long as your methods are valid, it should be no problem.
anonymous
  • anonymous
Thank you!
terenzreignz
  • terenzreignz
No problem :)

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