• Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Why does it not times the 2 (the radicand) as well?
anonymous
  • anonymous
Since it was in the parenthesis shouldn't it be multiplied too?
anonymous
  • anonymous
or do you not times the radicand when finding the perimeter of a rectangle?

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More answers

ash2326
  • ash2326
Where do you have doubt in this? \[2(\sqrt{128}+\sqrt{200})= 2(8 \sqrt 2+ 10 \sqrt 2)= 2(18 \sqrt 2)=36 \sqrt 2\]
ash2326
  • ash2326
@that1chick
anonymous
  • anonymous
2(√128+√200)=2(8√2+10√2)=2(18√2)=36√2 or 36√4?
anonymous
  • anonymous
sorry my computer is being slow
anonymous
  • anonymous
I just need to know if you times the radicand?
EvonHowell
  • EvonHowell
Well, wouldn't you ask that in the other question ask the person who posted it?
ash2326
  • ash2326
you have \[2\times18 \sqrt {2}\] you'll just multiply it by 18 \[36\sqrt 2\]
anonymous
  • anonymous
It was posted a while ago... and I did
ash2326
  • ash2326
@EvonHowell it's ok to ask as a new post. It's related to maths
anonymous
  • anonymous
so in 2(18√2) you would only times the 18 by 2?
ash2326
  • ash2326
@that1chick If you have \[2\sqrt 2\] then it's two times the radicand
ash2326
  • ash2326
yes, if you have \[2\times (4\times 6)\] Would you multiply it to both 4 and 6?
EvonHowell
  • EvonHowell
Yes, I know it is I was just saying.. LOL but that question was asked 5 Months ago so I understand now :)
ash2326
  • ash2326
Cool :)
ash2326
  • ash2326
@that1chick do you get my point?
anonymous
  • anonymous
Ok I get it... they shouldnt have put it in parenthesis. Thank you
ash2326
  • ash2326
Nope, they can put in parenthesis. If you have \[a(b+c)=a\times b+a\times c\] \[a(b\times c)=(a\times b)c=a\times b\times c\]
anonymous
  • anonymous
are you saying that it didnt change the radicand because it was applied to the value being times by the radical and therefor would be applied that way
ash2326
  • ash2326
It's applied to the whole term if you have 2 *(4*6) you apply 2 to either 4 or 6 not both. In our case we have a radical so it's applied to 18, it can be applied to radical also \[2\times (18\sqrt {2})=18\times 2\sqrt 2\] Take the 2 inside \[18\times \sqrt{4\times 2}=18\sqrt 8\] radical is just a no.
anonymous
  • anonymous
Oh okay... x the other value makes it towhere you dont have to simplify again... I get it now, thank you
ash2326
  • ash2326
Good :) welcome

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