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Why does it not times the 2 (the radicand) as well?
Since it was in the parenthesis shouldn't it be multiplied too?
or do you not times the radicand when finding the perimeter of a rectangle?

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Other answers:

Where do you have doubt in this? \[2(\sqrt{128}+\sqrt{200})= 2(8 \sqrt 2+ 10 \sqrt 2)= 2(18 \sqrt 2)=36 \sqrt 2\]
2(√128+√200)=2(8√2+10√2)=2(18√2)=36√2 or 36√4?
sorry my computer is being slow
I just need to know if you times the radicand?
Well, wouldn't you ask that in the other question ask the person who posted it?
you have \[2\times18 \sqrt {2}\] you'll just multiply it by 18 \[36\sqrt 2\]
It was posted a while ago... and I did
@EvonHowell it's ok to ask as a new post. It's related to maths
so in 2(18√2) you would only times the 18 by 2?
@that1chick If you have \[2\sqrt 2\] then it's two times the radicand
yes, if you have \[2\times (4\times 6)\] Would you multiply it to both 4 and 6?
Yes, I know it is I was just saying.. LOL but that question was asked 5 Months ago so I understand now :)
Cool :)
@that1chick do you get my point?
Ok I get it... they shouldnt have put it in parenthesis. Thank you
Nope, they can put in parenthesis. If you have \[a(b+c)=a\times b+a\times c\] \[a(b\times c)=(a\times b)c=a\times b\times c\]
are you saying that it didnt change the radicand because it was applied to the value being times by the radical and therefor would be applied that way
It's applied to the whole term if you have 2 *(4*6) you apply 2 to either 4 or 6 not both. In our case we have a radical so it's applied to 18, it can be applied to radical also \[2\times (18\sqrt {2})=18\times 2\sqrt 2\] Take the 2 inside \[18\times \sqrt{4\times 2}=18\sqrt 8\] radical is just a no.
Oh okay... x the other value makes it towhere you dont have to simplify again... I get it now, thank you
Good :) welcome

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