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that1chick
 2 years ago
Hey, I had a question about an answer on a question... please look at
http://openstudy.com/study#/updates/5054c511e4b0a91cdf44666c
and answer my question
that1chick
 2 years ago
Hey, I had a question about an answer on a question... please look at http://openstudy.com/study#/updates/5054c511e4b0a91cdf44666c and answer my question

This Question is Closed

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1Why does it not times the 2 (the radicand) as well?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1Since it was in the parenthesis shouldn't it be multiplied too?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1or do you not times the radicand when finding the perimeter of a rectangle?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1Where do you have doubt in this? \[2(\sqrt{128}+\sqrt{200})= 2(8 \sqrt 2+ 10 \sqrt 2)= 2(18 \sqrt 2)=36 \sqrt 2\]

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.12(√128+√200)=2(8√2+10√2)=2(18√2)=36√2 or 36√4?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1sorry my computer is being slow

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1I just need to know if you times the radicand?

EvonHowell
 2 years ago
Best ResponseYou've already chosen the best response.0Well, wouldn't you ask that in the other question ask the person who posted it?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1you have \[2\times18 \sqrt {2}\] you'll just multiply it by 18 \[36\sqrt 2\]

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1It was posted a while ago... and I did

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1@EvonHowell it's ok to ask as a new post. It's related to maths

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1so in 2(18√2) you would only times the 18 by 2?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1@that1chick If you have \[2\sqrt 2\] then it's two times the radicand

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1yes, if you have \[2\times (4\times 6)\] Would you multiply it to both 4 and 6?

EvonHowell
 2 years ago
Best ResponseYou've already chosen the best response.0Yes, I know it is I was just saying.. LOL but that question was asked 5 Months ago so I understand now :)

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1@that1chick do you get my point?

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1Ok I get it... they shouldnt have put it in parenthesis. Thank you

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1Nope, they can put in parenthesis. If you have \[a(b+c)=a\times b+a\times c\] \[a(b\times c)=(a\times b)c=a\times b\times c\]

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1are you saying that it didnt change the radicand because it was applied to the value being times by the radical and therefor would be applied that way

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1It's applied to the whole term if you have 2 *(4*6) you apply 2 to either 4 or 6 not both. In our case we have a radical so it's applied to 18, it can be applied to radical also \[2\times (18\sqrt {2})=18\times 2\sqrt 2\] Take the 2 inside \[18\times \sqrt{4\times 2}=18\sqrt 8\] radical is just a no.

that1chick
 2 years ago
Best ResponseYou've already chosen the best response.1Oh okay... x the other value makes it towhere you dont have to simplify again... I get it now, thank you
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