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A simple Utube that is open at both ends is partially filled with water (d=1000kg/m^3). now a liquid of density d is poured into left arm. it d of liquid surface in the left does not mix with water. it is observed that height of liquid surface in the left arm is 2cm more than height of water surface in left arm.
what is density d of the liquid?
 one year ago
 one year ago
A simple Utube that is open at both ends is partially filled with water (d=1000kg/m^3). now a liquid of density d is poured into left arm. it d of liquid surface in the left does not mix with water. it is observed that height of liquid surface in the left arm is 2cm more than height of water surface in left arm. what is density d of the liquid?
 one year ago
 one year ago

This Question is Closed

yrelhan4Best ResponseYou've already chosen the best response.1
ok so whenever i have done these kind of problems i have always known length of liquid column in the left arm. but not in this question. so how should i start?
 one year ago

MashyBest ResponseYou've already chosen the best response.0
wait.. lemme read the question properly!! :P
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
correction: water surface in the right arm.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
and are you sure its the 2cm more than LEFT arm itself?? so basically its saying the length fo the column of the liquid itself is 2cm :O :O :O!!!!
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
dw:1361214865922:dw
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
length of column isnt 2cm. in the second question they have asked length of the column.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
it does. but there is still a constant 'a'. how do i eliminate that? where do i apply the pressure equation?
 one year ago

MashyBest ResponseYou've already chosen the best response.0
wait lemme think :P hey what happens if you apply pressure equation for the UPPER LINE level?? left side is pressure due to atm and 2 cm of liquid right side is pressure due to atm only
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
:O idk what happens. nice man. you are intelligent. :P
 one year ago

MashyBest ResponseYou've already chosen the best response.0
no.. ther is something wrong.. there is something m missing.. you can't do that.. !! :O
 one year ago

MashyBest ResponseYou've already chosen the best response.0
what why not?? if you equate them.. you ll get the pressure due to 2cm liquid to be zero!!.. cause patm cancel out on both sides!
 one year ago

MashyBest ResponseYou've already chosen the best response.0
am i too sleepy!??? i just went to my textbooks.. and you can do that for all problems!! consider at the surface of the liquid in the column which is lower.... !?? tell me ?? whats wrong if we do that ?
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
dw:1361216017495:dw
 one year ago

MashyBest ResponseYou've already chosen the best response.0
not that.. !! dw:1361216075828:dw
 one year ago

MashyBest ResponseYou've already chosen the best response.0
you could do that for all problems.. and the density of all liquids would come zero! :/
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
i'm sorry. no ideas whats wrong. i have done 56 problems like this and i have never seen a the level at the surface of a liquid. why not? i dont know.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
even i dunno!!.. this is insane.. anwyays.. i think you can tke for the lower line ... in that case, the height of the liquid would be a +2... and the height of the water would be just a.. lol.. i dunno if that works :D
 one year ago

MashyBest ResponseYou've already chosen the best response.0
maybe you shouldnt consider at the surface... cause on one side its liquid and the other side its air.. so the pressures really need not be the same!!
 one year ago

MashyBest ResponseYou've already chosen the best response.0
but still thats not convincing me.. DAMN YOU.. its already 1.15 am here and now i can't sleep!! argggg
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
haha. spend sometime on this question. maybe it'll help you to sleep. :P
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
dg(a+2)=1000ga. makes sense? refer to mashy's diagram.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
yea but how will you solve that??????? but my question is.. why can't we ever consider at the surface???
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
lol. how would you eliminate a? another equation? what would it be?
 one year ago

MashyBest ResponseYou've already chosen the best response.0
something is missing in your question.. too ambiguous !! ll post a new question.. wait!!
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
well its what the book says. idk,
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
ooh i got it. just a sec
 one year ago

MashyBest ResponseYou've already chosen the best response.0
quick.. i need to sleep!! :P
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
use the buoyant force equation for the new liquid. you get dgA(a+2)=1000gAa get an equation for d in terms of a and substitute it into the first equation.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
A is the area of cross section of the tube
 one year ago

MashyBest ResponseYou've already chosen the best response.0
doesn't that give you back the same equation!?!? :P
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
lolol i just realized that xD
 one year ago

MashyBest ResponseYou've already chosen the best response.0
you are just running in circles.. omg.. our smartscores are at the stake here rajath's being the most LOLZZ :D
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
hey but there is this one thing. why does it look like the pressure exerted by the 2cm column is 0?
 one year ago

MashyBest ResponseYou've already chosen the best response.0
thats the problem m trying to tackle from that time.. if you consider pressure equation at the surface.. every problem gives you answer as zero.. something is horribly wrong with logic.. check my question.. its at the top!!
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
^ that is what mashy is being mad about.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
lol mashy i know i have to brush up on my skillzzzz :P but i'm not letting this one go
 one year ago

MashyBest ResponseYou've already chosen the best response.0
You calling in heavy reinforcements i see :D
 one year ago

MashyBest ResponseYou've already chosen the best response.0
dude.. i seriously believe the question does not give enough data!!.. try thinking practically!!!.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
hmm maybe. i think i'll let this one go. :P
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
yeah something tells me that 'a' should've been given. But the way this problem is sentenced makes me think otherwise.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
i am more worried about what i was addressing lolzzz..!!! but i think the solution to my problem is.. that you cannot use pressure equation at that level, the surface or any level above that.. cause unlike liquids.. we don't have an equation for the pressure due to atmosphere for a depth !!.. so maybe its forbidden..!! but i really need a better answer !!
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
anyway, i'm gonna go now. you guys scratch your brains. :P
 one year ago

MashyBest ResponseYou've already chosen the best response.0
no m leaving as well.. thanks for dragging me into this.. really.. now i have something to think about.. so ll give you a medal :D and i ll fan yu :D
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
i got it! i know why we can't say that the pressure due to the 2cm is not 0.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
you mean what we can't say that the pressure due to 2cm IS zero?
 one year ago

MashyBest ResponseYou've already chosen the best response.0
dazzle me .. quick quick!!!
 one year ago

MashyBest ResponseYou've already chosen the best response.0
did you fall asleep or something?!?!?
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
lmao ok think of the whole liquid column as a solid. the 2cm column is like the part of an iceberg that sticks out of the water surface. it's being held up and not allowed to sink beyond that level because the part of the same liquid below it is applying a force equal to it's weight.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
and how does this solve the problem of pressure you ask. I'll tell you how.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
didn't we learn that the molecules inside a liquid are pulled equally by the other molecules? (i remember learning this while learning about surface tension) so, AT THAT LEVEL and AT EVERY LEVEL IN THAT MYSTERY LIQUID, the pressure is the same and it's equal to the atmospheric pressure.
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
I could be COMPLETELY WRONG but lemme think about it a little bit more.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
*yawn* goodnight both of you! :P
 one year ago

MashyBest ResponseYou've already chosen the best response.0
first of all you can't treat it like a solid.. cause fluid mechanics doesn't hold good for solid!! :P.. but wait.. m thinking!!
 one year ago

MashyBest ResponseYou've already chosen the best response.0
yrelhan4.. if i ever meet you .. remind me to first kill you :D
 one year ago

MashyBest ResponseYou've already chosen the best response.0
dw:1361219680403:dw if what you are saying is true.. (whatever that is :D) if it applies at level 1, why doesn't it apply at level 2?? why isn't level 2 at atm pressure??
 one year ago

MashyBest ResponseYou've already chosen the best response.0
dw:1361219869615:dw a better picture :P
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
you're right....obviously there is a gap in my understanding of this part of the universe.
 one year ago

MashyBest ResponseYou've already chosen the best response.0
or maybe we found a flaw in mechanics.. quickly lemme patent this.. before you steal away my query :D
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
Mark my words  I will get to the bottom of this (if vincent doesn't answer first :P) in less than 24 hours from now. (and lol ^)
 one year ago

MashyBest ResponseYou've already chosen the best response.0
K i really need to sleep now.. so ll go now .. .bye bye.. lets discuss tihs with someone who actually knows physics lol :D !! m ashamed to call myself physics teacher now!
 one year ago

rajathsbhatBest ResponseYou've already chosen the best response.0
see ya tomorrow. this is a wake up call for me. Time to whip out those dusty old physics books :P
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
ok so got it guys. the options are 1000,1200,1400,800 kg/m^3 according to equation dg(a+2)=1000ga, obviously d<1000, so that would mean d=800. so that is that. thank you for wasting your time on this question. :P cheers!
 one year ago
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