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yrelhan4 Group Title

A simple U-tube that is open at both ends is partially filled with water (d=1000kg/m^3). now a liquid of density d is poured into left arm. it d of liquid surface in the left does not mix with water. it is observed that height of liquid surface in the left arm is 2cm more than height of water surface in left arm. what is density d of the liquid?

  • one year ago
  • one year ago

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  1. yrelhan4 Group Title
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    ok so whenever i have done these kind of problems i have always known length of liquid column in the left arm. but not in this question. so how should i start?

    • one year ago
  2. yrelhan4 Group Title
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    @Mashy

    • one year ago
  3. Mashy Group Title
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    wait.. lemme read the question properly!! :P

    • one year ago
  4. Mashy Group Title
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    draw.. first draw.. !!

    • one year ago
  5. yrelhan4 Group Title
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    correction: water surface in the right arm.

    • one year ago
  6. Mashy Group Title
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    and are you sure its the 2cm more than LEFT arm itself?? so basically its saying the length fo the column of the liquid itself is 2cm :O :O :O!!!!

    • one year ago
  7. yrelhan4 Group Title
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    |dw:1361214865922:dw|

    • one year ago
  8. yrelhan4 Group Title
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    length of column isnt 2cm. in the second question they have asked length of the column.

    • one year ago
  9. Mashy Group Title
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    |dw:1361214958351:dw|

    • one year ago
  10. Mashy Group Title
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    does that make sense?

    • one year ago
  11. yrelhan4 Group Title
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    it does. but there is still a constant 'a'. how do i eliminate that? where do i apply the pressure equation?

    • one year ago
  12. Mashy Group Title
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    wait lemme think :P hey what happens if you apply pressure equation for the UPPER LINE level?? left side is pressure due to atm and 2 cm of liquid right side is pressure due to atm only

    • one year ago
  13. yrelhan4 Group Title
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    :O idk what happens. nice man. you are intelligent. :P

    • one year ago
  14. Mashy Group Title
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    no.. ther is something wrong.. there is something m missing.. you can't do that.. !! :O

    • one year ago
  15. yrelhan4 Group Title
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    why not?

    • one year ago
  16. Mashy Group Title
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    what why not?? if you equate them.. you ll get the pressure due to 2cm liquid to be zero!!.. cause patm cancel out on both sides!

    • one year ago
  17. yrelhan4 Group Title
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    hmm. sure. :P

    • one year ago
  18. Mashy Group Title
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    am i too sleepy!??? i just went to my textbooks.. and you can do that for all problems!! consider at the surface of the liquid in the column which is lower.... !?? tell me ?? whats wrong if we do that ?

    • one year ago
  19. yrelhan4 Group Title
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    |dw:1361216017495:dw|

    • one year ago
  20. Mashy Group Title
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    not that.. !! |dw:1361216075828:dw|

    • one year ago
  21. Mashy Group Title
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    you could do that for all problems.. and the density of all liquids would come zero! :-/

    • one year ago
  22. yrelhan4 Group Title
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    i'm sorry. no ideas whats wrong. i have done 5-6 problems like this and i have never seen a the level at the surface of a liquid. why not? i dont know.

    • one year ago
  23. Mashy Group Title
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    even i dunno!!.. this is insane.. anwyays.. i think you can tke for the lower line ... in that case, the height of the liquid would be a +2... and the height of the water would be just a.. lol.. i dunno if that works :D

    • one year ago
  24. Mashy Group Title
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    maybe you shouldnt consider at the surface... cause on one side its liquid and the other side its air.. so the pressures really need not be the same!!

    • one year ago
  25. Mashy Group Title
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    yea that must be it :P

    • one year ago
  26. yrelhan4 Group Title
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    haha. alright. :P

    • one year ago
  27. Mashy Group Title
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    but still thats not convincing me.. DAMN YOU.. its already 1.15 am here and now i can't sleep!! argggg

    • one year ago
  28. rajathsbhat Group Title
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    it's simple guys

    • one year ago
  29. yrelhan4 Group Title
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    haha. spend sometime on this question. maybe it'll help you to sleep. :P

    • one year ago
  30. Mashy Group Title
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    plz rajath.. tel why !!

    • one year ago
  31. rajathsbhat Group Title
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    dg(a+2)=1000ga. makes sense? refer to mashy's diagram.

    • one year ago
  32. Mashy Group Title
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    yea but how will you solve that??????? but my question is.. why can't we ever consider at the surface???

    • one year ago
  33. yrelhan4 Group Title
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    lol. how would you eliminate a? another equation? what would it be?

    • one year ago
  34. Mashy Group Title
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    something is missing in your question.. too ambiguous !! ll post a new question.. wait!!

    • one year ago
  35. rajathsbhat Group Title
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    ^ikr

    • one year ago
  36. yrelhan4 Group Title
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    well its what the book says. idk,

    • one year ago
  37. rajathsbhat Group Title
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    ooh i got it. just a sec

    • one year ago
  38. Mashy Group Title
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    quick.. i need to sleep!! :P

    • one year ago
  39. rajathsbhat Group Title
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    use the buoyant force equation for the new liquid. you get dgA(a+2)=1000gAa get an equation for d in terms of a and substitute it into the first equation.

    • one year ago
  40. rajathsbhat Group Title
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    A is the area of cross section of the tube

    • one year ago
  41. Mashy Group Title
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    doesn't that give you back the same equation!?!? :P

    • one year ago
  42. rajathsbhat Group Title
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    lolol i just realized that xD

    • one year ago
  43. yrelhan4 Group Title
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    lol. it does. :P

    • one year ago
  44. Mashy Group Title
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    you are just running in circles.. omg.. our smartscores are at the stake here rajath's being the most LOLZZ :D

    • one year ago
  45. rajathsbhat Group Title
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    hey but there is this one thing. why does it look like the pressure exerted by the 2cm column is 0?

    • one year ago
  46. Mashy Group Title
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    thats the problem m trying to tackle from that time.. if you consider pressure equation at the surface.. every problem gives you answer as zero.. something is horribly wrong with logic.. check my question.. its at the top!!

    • one year ago
  47. yrelhan4 Group Title
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    ^ that is what mashy is being mad about.

    • one year ago
  48. rajathsbhat Group Title
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    lol mashy i know i have to brush up on my skillzzzz :P but i'm not letting this one go

    • one year ago
  49. yrelhan4 Group Title
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    thats the spirit :P

    • one year ago
  50. yrelhan4 Group Title
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    @Vincent-Lyon.Fr

    • one year ago
  51. Mashy Group Title
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    You calling in heavy reinforcements i see :D

    • one year ago
  52. Mashy Group Title
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    dude.. i seriously believe the question does not give enough data!!.. try thinking practically!!!.

    • one year ago
  53. yrelhan4 Group Title
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    hmm maybe. i think i'll let this one go. :P

    • one year ago
  54. rajathsbhat Group Title
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    yeah something tells me that 'a' should've been given. But the way this problem is sentenced makes me think otherwise.

    • one year ago
  55. Mashy Group Title
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    i am more worried about what i was addressing lolzzz..!!! but i think the solution to my problem is.. that you cannot use pressure equation at that level, the surface or any level above that.. cause unlike liquids.. we don't have an equation for the pressure due to atmosphere for a depth !!.. so maybe its forbidden..!! but i really need a better answer !!

    • one year ago
  56. yrelhan4 Group Title
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    anyway, i'm gonna go now. you guys scratch your brains. :P

    • one year ago
  57. Mashy Group Title
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    no m leaving as well.. thanks for dragging me into this.. really.. now i have something to think about.. so ll give you a medal :D and i ll fan yu :D

    • one year ago
  58. rajathsbhat Group Title
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    i got it! i know why we can't say that the pressure due to the 2cm is not 0.

    • one year ago
  59. Mashy Group Title
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    you mean what we can't say that the pressure due to 2cm IS zero?

    • one year ago
  60. rajathsbhat Group Title
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    yes

    • one year ago
  61. Mashy Group Title
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    dazzle me .. quick quick!!!

    • one year ago
  62. Mashy Group Title
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    did you fall asleep or something?!?!?

    • one year ago
  63. rajathsbhat Group Title
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    lmao ok think of the whole liquid column as a solid. the 2cm column is like the part of an iceberg that sticks out of the water surface. it's being held up and not allowed to sink beyond that level because the part of the same liquid below it is applying a force equal to it's weight.

    • one year ago
  64. rajathsbhat Group Title
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    and how does this solve the problem of pressure you ask. I'll tell you how.

    • one year ago
  65. rajathsbhat Group Title
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    didn't we learn that the molecules inside a liquid are pulled equally by the other molecules? (i remember learning this while learning about surface tension) so, AT THAT LEVEL and AT EVERY LEVEL IN THAT MYSTERY LIQUID, the pressure is the same and it's equal to the atmospheric pressure.

    • one year ago
  66. Mashy Group Title
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    wait wait wait.. !!

    • one year ago
  67. rajathsbhat Group Title
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    I could be COMPLETELY WRONG but lemme think about it a little bit more.

    • one year ago
  68. yrelhan4 Group Title
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    *yawn* goodnight both of you! :P

    • one year ago
  69. Mashy Group Title
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    first of all you can't treat it like a solid.. cause fluid mechanics doesn't hold good for solid!! :P.. but wait.. m thinking!!

    • one year ago
  70. Mashy Group Title
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    yrelhan4.. if i ever meet you .. remind me to first kill you :D

    • one year ago
  71. Mashy Group Title
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    |dw:1361219680403:dw| if what you are saying is true.. (whatever that is :D) if it applies at level 1, why doesn't it apply at level 2?? why isn't level 2 at atm pressure??

    • one year ago
  72. Mashy Group Title
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    |dw:1361219869615:dw| a better picture :P

    • one year ago
  73. rajathsbhat Group Title
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    you're right....obviously there is a gap in my understanding of this part of the universe.

    • one year ago
  74. Mashy Group Title
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    or maybe we found a flaw in mechanics.. quickly lemme patent this.. before you steal away my query :D

    • one year ago
  75. rajathsbhat Group Title
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    Mark my words - I will get to the bottom of this (if vincent doesn't answer first :P) in less than 24 hours from now. (and lol ^)

    • one year ago
  76. Mashy Group Title
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    K i really need to sleep now.. so ll go now .. .bye bye.. lets discuss tihs with someone who actually knows physics lol :D !! m ashamed to call myself physics teacher now!

    • one year ago
  77. rajathsbhat Group Title
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    see ya tomorrow. this is a wake up call for me. Time to whip out those dusty old physics books :P

    • one year ago
  78. yrelhan4 Group Title
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    ok so got it guys. the options are 1000,1200,1400,800 kg/m^3 according to equation dg(a+2)=1000ga, obviously d<1000, so that would mean d=800. so that is that. thank you for wasting your time on this question. :P cheers!

    • one year ago
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