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A simple U-tube that is open at both ends is partially filled with water (d=1000kg/m^3). now a liquid of density d is poured into left arm. it d of liquid surface in the left does not mix with water. it is observed that height of liquid surface in the left arm is 2cm more than height of water surface in left arm. what is density d of the liquid?

Physics
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ok so whenever i have done these kind of problems i have always known length of liquid column in the left arm. but not in this question. so how should i start?
wait.. lemme read the question properly!! :P

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Other answers:

draw.. first draw.. !!
correction: water surface in the right arm.
and are you sure its the 2cm more than LEFT arm itself?? so basically its saying the length fo the column of the liquid itself is 2cm :O :O :O!!!!
|dw:1361214865922:dw|
length of column isnt 2cm. in the second question they have asked length of the column.
|dw:1361214958351:dw|
does that make sense?
it does. but there is still a constant 'a'. how do i eliminate that? where do i apply the pressure equation?
wait lemme think :P hey what happens if you apply pressure equation for the UPPER LINE level?? left side is pressure due to atm and 2 cm of liquid right side is pressure due to atm only
:O idk what happens. nice man. you are intelligent. :P
no.. ther is something wrong.. there is something m missing.. you can't do that.. !! :O
why not?
what why not?? if you equate them.. you ll get the pressure due to 2cm liquid to be zero!!.. cause patm cancel out on both sides!
hmm. sure. :P
am i too sleepy!??? i just went to my textbooks.. and you can do that for all problems!! consider at the surface of the liquid in the column which is lower.... !?? tell me ?? whats wrong if we do that ?
|dw:1361216017495:dw|
not that.. !! |dw:1361216075828:dw|
you could do that for all problems.. and the density of all liquids would come zero! :-/
i'm sorry. no ideas whats wrong. i have done 5-6 problems like this and i have never seen a the level at the surface of a liquid. why not? i dont know.
even i dunno!!.. this is insane.. anwyays.. i think you can tke for the lower line ... in that case, the height of the liquid would be a +2... and the height of the water would be just a.. lol.. i dunno if that works :D
maybe you shouldnt consider at the surface... cause on one side its liquid and the other side its air.. so the pressures really need not be the same!!
yea that must be it :P
haha. alright. :P
but still thats not convincing me.. DAMN YOU.. its already 1.15 am here and now i can't sleep!! argggg
it's simple guys
haha. spend sometime on this question. maybe it'll help you to sleep. :P
plz rajath.. tel why !!
dg(a+2)=1000ga. makes sense? refer to mashy's diagram.
yea but how will you solve that??????? but my question is.. why can't we ever consider at the surface???
lol. how would you eliminate a? another equation? what would it be?
something is missing in your question.. too ambiguous !! ll post a new question.. wait!!
^ikr
well its what the book says. idk,
ooh i got it. just a sec
quick.. i need to sleep!! :P
use the buoyant force equation for the new liquid. you get dgA(a+2)=1000gAa get an equation for d in terms of a and substitute it into the first equation.
A is the area of cross section of the tube
doesn't that give you back the same equation!?!? :P
lolol i just realized that xD
lol. it does. :P
you are just running in circles.. omg.. our smartscores are at the stake here rajath's being the most LOLZZ :D
hey but there is this one thing. why does it look like the pressure exerted by the 2cm column is 0?
thats the problem m trying to tackle from that time.. if you consider pressure equation at the surface.. every problem gives you answer as zero.. something is horribly wrong with logic.. check my question.. its at the top!!
^ that is what mashy is being mad about.
lol mashy i know i have to brush up on my skillzzzz :P but i'm not letting this one go
thats the spirit :P
@Vincent-Lyon.Fr
You calling in heavy reinforcements i see :D
dude.. i seriously believe the question does not give enough data!!.. try thinking practically!!!.
hmm maybe. i think i'll let this one go. :P
yeah something tells me that 'a' should've been given. But the way this problem is sentenced makes me think otherwise.
i am more worried about what i was addressing lolzzz..!!! but i think the solution to my problem is.. that you cannot use pressure equation at that level, the surface or any level above that.. cause unlike liquids.. we don't have an equation for the pressure due to atmosphere for a depth !!.. so maybe its forbidden..!! but i really need a better answer !!
anyway, i'm gonna go now. you guys scratch your brains. :P
no m leaving as well.. thanks for dragging me into this.. really.. now i have something to think about.. so ll give you a medal :D and i ll fan yu :D
i got it! i know why we can't say that the pressure due to the 2cm is not 0.
you mean what we can't say that the pressure due to 2cm IS zero?
yes
dazzle me .. quick quick!!!
did you fall asleep or something?!?!?
lmao ok think of the whole liquid column as a solid. the 2cm column is like the part of an iceberg that sticks out of the water surface. it's being held up and not allowed to sink beyond that level because the part of the same liquid below it is applying a force equal to it's weight.
and how does this solve the problem of pressure you ask. I'll tell you how.
didn't we learn that the molecules inside a liquid are pulled equally by the other molecules? (i remember learning this while learning about surface tension) so, AT THAT LEVEL and AT EVERY LEVEL IN THAT MYSTERY LIQUID, the pressure is the same and it's equal to the atmospheric pressure.
wait wait wait.. !!
I could be COMPLETELY WRONG but lemme think about it a little bit more.
*yawn* goodnight both of you! :P
first of all you can't treat it like a solid.. cause fluid mechanics doesn't hold good for solid!! :P.. but wait.. m thinking!!
yrelhan4.. if i ever meet you .. remind me to first kill you :D
|dw:1361219680403:dw| if what you are saying is true.. (whatever that is :D) if it applies at level 1, why doesn't it apply at level 2?? why isn't level 2 at atm pressure??
|dw:1361219869615:dw| a better picture :P
you're right....obviously there is a gap in my understanding of this part of the universe.
or maybe we found a flaw in mechanics.. quickly lemme patent this.. before you steal away my query :D
Mark my words - I will get to the bottom of this (if vincent doesn't answer first :P) in less than 24 hours from now. (and lol ^)
K i really need to sleep now.. so ll go now .. .bye bye.. lets discuss tihs with someone who actually knows physics lol :D !! m ashamed to call myself physics teacher now!
see ya tomorrow. this is a wake up call for me. Time to whip out those dusty old physics books :P
ok so got it guys. the options are 1000,1200,1400,800 kg/m^3 according to equation dg(a+2)=1000ga, obviously d<1000, so that would mean d=800. so that is that. thank you for wasting your time on this question. :P cheers!

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