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anonymous
 3 years ago
find the integral.
anonymous
 3 years ago
find the integral.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361280612277:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have been trying to enter the site since yesterday did you all have the same problem?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0anyways there are many ways to solve this problem, one of them would be Taylor series the other one would be substitution method

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind yea ive been having problems with it to so i did the problems i know how to do until it finally works

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind i figured that one out im stuck on another one now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0evaluate the intergal dw:1361284859202:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind that one ^^^

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry i meant i was having problems entering the website since yesterday

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know how to solve both integral in my head

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind how long are you going to be one today ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it depends on my work, if i am busy or not

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you answer my question please?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0were you able to log on to the site

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathsmind which one ? lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh no i wasnt i answered it above

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this website? openstudy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i felt like crying lol, with out this website i don't know what id do

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me reply to the last integral

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the answer for the last integral would be pi/6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now by looking at the last integral you can find out from the table that it is equal to arcsin(x/2)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1}\frac{ dx }{ \sqrt{4x^2} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that the integral or not?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok there are two ways to do that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0one way is to look at the arctrigs integrals

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you know the table of integrals right!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the other way is to go through full substitution method

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol no but ill look them up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok do you want detailed solution then

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you differentiate the last bit?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{1}\frac{ 2du }{\sqrt{44u^2} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\limits_{0}^{1}\frac{ du }{\sqrt{1u^2} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your a math genuis lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thanks that was kind of you, and you are a bright student

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me give you a third way how to do that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i understand the usub the most

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have three more integral questions

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you need to know different methods to solve one problem , that for future note...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0altho the differentiate part is a bit hard

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i have a phone call but still submit your work

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but ill look back it later because i have to get this course done to graduate

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no i meant you make y =2sinx sub

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0different substitution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you look at the unit triangle you can figure out that you need a sin sub

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0find the intergal dw:1361286908472:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0again you are going to get an arctan but now we need to look at the factors

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just by looking at this integral we will get 4/3arctan(3x) +c

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the question is what was x=? in this u sub

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you need to assume that 3x=u, 9x^2=u^2, 3dx=du

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ 4du }{ 3(1+u^2) }=\frac{ 4 }{ 3}\arctan(u)+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[u=3x, \therefore \frac{ 4 }{ 3 }\arctan(3x)+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's your final answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay i just did the other one so i have one more integral question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361287534741:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0again you can see we will get the arctan + something

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your answer should be\[\frac{ 1 }{ 2 }\arctan(\frac{ 1 }{ 2}(x1))+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\limits\limits \frac{ dx }{4+(1x)^2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now 2u=1x, 4u^2=(1x)^2,

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now one thing you need to know is how to let the 4 be a one in the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me show, it is clear from the usub

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0remember that 2u =1x, 2du=dx

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay so far so good lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits\frac{ 2du }{4(1+(u)^2)}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you see it better this way?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ 2 }\arctan(u)+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[2u=1x, \space u=\frac{ 1 }{ 2 }(1x)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ 2 }\arctan(\frac{ 1 }{ 2 }(1x))+c\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's your final answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay thanks ! im working on some ill let you know if i need more help

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you don't sound like you got the last one?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol i havent fully looked at it yet im finishing a problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so i read your mind well hehehe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol yeahh i was wondering how you knew that,but im looking at it now

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i still don't understand how the engagement scheme works on open study

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think its by the questions you answer, and medals you receive

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no i am not asking about those two, i am asking about the engagement part

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the one that has learner next to it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol i thinks its from asking questions cause thats how you learn right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay i found two i need help on

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0determine which of the integrals can be found using the basic integration formulas you have studied so far in the text.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i think you need to open a new thread because this one is getting heavy with BW
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