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sarah.radke
Find the second term in this sequence: t sub n = (6 - n) ^2 a) 6 b) 36 c) 9 d) 16
I don't know exactly what is the problem. It's lack of something, because if it is as you write, it isn't any solution you give out. the sequence must start from somewhere like n=0, or n=1 or else. if it is as you state, just expand the square of the (6-n) and have the second term, if not, it should be \[\sum_{n=0}^{\infty} (tn)\]
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