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wats number 4??

^^^

ok so,
we have
n=100
x bar=80,000
sigma=15,000
and we need mu with a 95% confidence interval

|dw:1361314863406:dw|

Okay, so you seem to have it... two standard deviations above and below the mean.

what would be my final answer exactly?

50k -110k.

yeah, i did 80,000/ [15,000/ sqrt(100)] earlier and got 53.333....

"now you can find the interval that contains 95% of the area: ±1.96 s. d."
what do you mean?

?
I would do 80,000 ± 1.96*1,500 as the interval

yeah, 95 = 1.96 on the table

Oh, I misunderstood the question -- gotta read better. Phi's right about that.

why 1,500? shouldn't it be 15,000?

but why 1500? why not 15,000???

ok so the CI is (77,060, 82,940)

ok so i just need to find the mean of all the hours given

yes, that will correspond to the 80,000 in Q4

ok my final answer is (5.3, 10.7) when rounding off

right?

what did you get for the mean and std?
what sigma gives 90% confidence?

i did:
n=15
sigma=6.3
x bar=8
6.3/sqrt(15) = 1.63
90% CI = 1.645
8 +- (1.645 * 1.63)
(5.3, 10.7)

OK, I got the same numbers

shhweet

can i bother you for one more question? its the only i have left. ...#11

#11
part a, i got 81.6
and for part b, i got 159.6
but what about the error??

Score = B0 + B1 (Hours) + Error

I am wondering if the 159.6 is valid. I would think 100 is the best you can do.

yeah that's what i was thinking, so the error has to be a negative number

but where the heck would we get that number from the information provided?

If you get an answer, let me know. I only know enough of this stuff to be dangerous.

yeah, im trying to get some more help from someone cause i've obviously already tried on my own.

so 81.6 and 159.6 seem to be the correct answers?

seems a little too simple... idk

but i understand what you are saying