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iheartfood Group Title

#1: When you heat an air-filled balloon, what happens inside with regard to the movement of air molecules? A. The collisions of air molecules against the wall of the balloon are weaker. B. The collisions of air molecules against the wall of the balloon are stronger. C. The collisions of air molecules against the wall of the balloon do not change. **my answer: B is that right?? @aaronq :)

  • one year ago
  • one year ago

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  1. iheartfood Group Title
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    #2: You have 0.5 L of air at 203 K in an expandable container at constant pressure. You heat the container to 273 K. What is the volume of air? A. 0.37 L B. 0.67 L C. 1.5 L D. 0.25 L **myanswer: B. 0.67 L is that right?

    • one year ago
  2. iheartfood Group Title
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    #3: You place a balloon in a closed vacuum chamber at standard temperature and pressure (STP). You decrease the chamber temperature by half but keep the pressure constant. What happens to the balloon? A. It reduces in size by half. B, It stays the same volume. C. It doubles in volume. D. It expands to four times the original volume. *my answer: A is that irhgt?

    • one year ago
  3. aaronq Group Title
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    they both are correct

    • one year ago
  4. aaronq Group Title
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    3 is good too

    • one year ago
  5. iheartfood Group Title
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    #4: A balloon contains 0.5 L of air at 273 K. Its volume increases to volume of 0.75 L at constant pressure. What is the temperature of air inside the balloon? A. 137 K B. 182 K C. 205 K D. 410 K **my answer: D. 410 K is that right?? and yayy :)

    • one year ago
  6. aaronq Group Title
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    for #4, if you increase the volume the temp will go down

    • one year ago
  7. iheartfood Group Title
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    #5: This question appears on a quiz. "A 1.0 L balloon has a temperature of 273 K. When the temperature changes to 30°C, what is the volume?" A student answers 0.11 L. Which of the following explanations is true? (C = K 273; K = C + 273.) A. The student did not solve for the correct parameter, and the answer should be 1.11 L. B. The student did not solve for the correct parameter, and the answer should be 0.90 L. C. The student did not put the temperatures in the same units, and the answer should be 0.90 L. D. The student did not put the temperatures in the same units, and the answer should be 1.11 L. **My answer: D not too sure tho... is that right? :/

    • one year ago
  8. iheartfood Group Title
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    so #4 is wrong then>?? idk what it is :(

    • one year ago
  9. aaronq Group Title
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    for #4, you use P1V1=P2V2 plug the numbers in and you can't ever get a wrong answer.. unless you put them in the wrong place

    • one year ago
  10. iheartfood Group Title
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    i don't even know haha :/ like how do u plug them in? cuz i definitely didn't do it right :/

    • one year ago
  11. aaronq Group Title
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    for #5, the "student" divided 30/273.. so i would say wrong parameters.. idk how someone would do that though

    • one year ago
  12. iheartfood Group Title
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    like what goes where?

    • one year ago
  13. iheartfood Group Title
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    wait so the answer to #5 is this? A. The student did not solve for the correct parameter, and the answer should be 1.11 L.

    • one year ago
  14. aaronq Group Title
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    P=pressure V= volume on one side is the set for the system at one point, then across the equal sign for the change

    • one year ago
  15. aaronq Group Title
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    for #5, 1.11L is not the correct answer...

    • one year ago
  16. iheartfood Group Title
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    so #5 is B. The student did not solve for the correct parameter, and the answer should be 0.90 L. ???? and I'm confused about #4 now haha :/ could u pls show me how u do it? :/

    • one year ago
  17. iheartfood Group Title
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    heres how i think it is based off what u said.. :/ .5/273=.75/x and solve for x? is that right?

    • one year ago
  18. iheartfood Group Title
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    and i got x=409.5 which is about 410K.. which is D.. but you said that #4 isn't D right?? :/ so i don't know what to do now :( @aaronq what do i do for it then?

    • one year ago
  19. aaronq Group Title
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    no they're not being divided

    • one year ago
  20. aaronq Group Title
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    PV=nRT it's basically based off the ideal gas law, PV/nRT of one system equals PV/nRT of the other \[\frac{ P _{1}V _{1} }{ n _{1}RT _{1} }=\frac{ P _{2}V _{2} }{ n _{2}RT _{2} }\] when all the variables like T or n are constant, it simplifies to P1V1=P2V2

    • one year ago
  21. iheartfood Group Title
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    okay so how do i apply that with the values that they give me?

    • one year ago
  22. aaronq Group Title
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    so for number 4, (0.5 L)(273 K)= (0.75 L)(T) (0.5 L)(273 K)/(0.75 L) = T

    • one year ago
  23. iheartfood Group Title
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    oh so i get 182.. which is answer choice B right?

    • one year ago
  24. iheartfood Group Title
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    and was #5's answer B. The student did not solve for the correct parameter, and the answer should be 0.90 L. ??

    • one year ago
  25. aaronq Group Title
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    yes

    • one year ago
  26. iheartfood Group Title
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    yes to both 4 and 5? haha

    • one year ago
  27. aaronq Group Title
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    4 yes, 5 idk the student did both, not change his temperature units, and divided the wrong way...

    • one year ago
  28. iheartfood Group Title
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    okay... so which would u go with for 5?? cuz idk haha

    • one year ago
  29. aaronq Group Title
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    i would go with C, because the student still got an answer in litres... somehow lol

    • one year ago
  30. iheartfood Group Title
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    okay haha :) thanks!!!:)

    • one year ago
  31. aaronq Group Title
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    no prob! :)

    • one year ago
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