## Skeeza Can someone help me simplify this radical expression, please? √45n^5 Also can you tell me how you did it? one year ago one year ago

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1. satellite73

i take it is $\sqrt{45n^5}$ right?

2. satellite73

first step is to factor $$45=9\times 5$$ and this helps because you know what the square root of 9 is, namely 3 you can write $\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}$

3. satellite73

we can take care of $$\sqrt{n^5}$$ in your head two goes in to 5 twice, with a remainder of 1, so $$n^2$$ comes out of the radical and one $$n$$ stays in, making $$\sqrt{n^5}=n^2\sqrt{n}$$

4. Skeeza

Okay hold on let me write this down

5. Skeeza

i don't understand

6. mushinni

@satellite73 how did you get rid of the 5?

7. mushinni

in the last step

8. Ken&Riss

He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2

9. tem0c_00

I still don't get it

10. tem0c_00

can I plz get some help