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Skeeza
 2 years ago
Can someone help me simplify this radical expression, please?
√45n^5
Also can you tell me how you did it?
Skeeza
 2 years ago
Can someone help me simplify this radical expression, please? √45n^5 Also can you tell me how you did it?

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satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0i take it is \[\sqrt{45n^5}\] right?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0first step is to factor \(45=9\times 5\) and this helps because you know what the square root of 9 is, namely 3 you can write \[\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.0we can take care of \(\sqrt{n^5}\) in your head two goes in to 5 twice, with a remainder of 1, so \(n^2\) comes out of the radical and one \(n\) stays in, making \(\sqrt{n^5}=n^2\sqrt{n}\)

Skeeza
 2 years ago
Best ResponseYou've already chosen the best response.0Okay hold on let me write this down

mushinni
 2 years ago
Best ResponseYou've already chosen the best response.0@satellite73 how did you get rid of the 5?

Ken&Riss
 2 years ago
Best ResponseYou've already chosen the best response.0He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2

tem0c_00
 one year ago
Best ResponseYou've already chosen the best response.0can I plz get some help
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