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Skeeza
Group Title
Can someone help me simplify this radical expression, please?
√45n^5
Also can you tell me how you did it?
 one year ago
 one year ago
Skeeza Group Title
Can someone help me simplify this radical expression, please? √45n^5 Also can you tell me how you did it?
 one year ago
 one year ago

This Question is Open

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
i take it is \[\sqrt{45n^5}\] right?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
first step is to factor \(45=9\times 5\) and this helps because you know what the square root of 9 is, namely 3 you can write \[\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
we can take care of \(\sqrt{n^5}\) in your head two goes in to 5 twice, with a remainder of 1, so \(n^2\) comes out of the radical and one \(n\) stays in, making \(\sqrt{n^5}=n^2\sqrt{n}\)
 one year ago

Skeeza Group TitleBest ResponseYou've already chosen the best response.0
Okay hold on let me write this down
 one year ago

Skeeza Group TitleBest ResponseYou've already chosen the best response.0
i don't understand
 one year ago

mushinni Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 how did you get rid of the 5?
 one year ago

mushinni Group TitleBest ResponseYou've already chosen the best response.0
in the last step
 one year ago

Ken&Riss Group TitleBest ResponseYou've already chosen the best response.0
He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2
 11 months ago

tem0c_00 Group TitleBest ResponseYou've already chosen the best response.0
I still don't get it
 10 months ago

tem0c_00 Group TitleBest ResponseYou've already chosen the best response.0
can I plz get some help
 10 months ago
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