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Can someone help me simplify this radical expression, please?
√45n^5
Also can you tell me how you did it?
 one year ago
 one year ago
Can someone help me simplify this radical expression, please? √45n^5 Also can you tell me how you did it?
 one year ago
 one year ago

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satellite73Best ResponseYou've already chosen the best response.0
i take it is \[\sqrt{45n^5}\] right?
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
first step is to factor \(45=9\times 5\) and this helps because you know what the square root of 9 is, namely 3 you can write \[\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
we can take care of \(\sqrt{n^5}\) in your head two goes in to 5 twice, with a remainder of 1, so \(n^2\) comes out of the radical and one \(n\) stays in, making \(\sqrt{n^5}=n^2\sqrt{n}\)
 one year ago

SkeezaBest ResponseYou've already chosen the best response.0
Okay hold on let me write this down
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
@satellite73 how did you get rid of the 5?
 one year ago

Ken&RissBest ResponseYou've already chosen the best response.0
He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2
 8 months ago

tem0c_00Best ResponseYou've already chosen the best response.0
can I plz get some help
 7 months ago
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