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Skeeza Group Title

Can someone help me simplify this radical expression, please? √45n^5 Also can you tell me how you did it?

  • one year ago
  • one year ago

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  1. satellite73 Group Title
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    i take it is \[\sqrt{45n^5}\] right?

    • one year ago
  2. satellite73 Group Title
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    first step is to factor \(45=9\times 5\) and this helps because you know what the square root of 9 is, namely 3 you can write \[\sqrt{45n^5}=\sqrt{9\times 5\times n^4\times n}=\sqrt{9}\sqrt{n^4}\sqrt{5n}=3n^2\sqrt{5n}\]

    • one year ago
  3. satellite73 Group Title
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    we can take care of \(\sqrt{n^5}\) in your head two goes in to 5 twice, with a remainder of 1, so \(n^2\) comes out of the radical and one \(n\) stays in, making \(\sqrt{n^5}=n^2\sqrt{n}\)

    • one year ago
  4. Skeeza Group Title
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    Okay hold on let me write this down

    • one year ago
  5. Skeeza Group Title
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    i don't understand

    • one year ago
  6. mushinni Group Title
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    @satellite73 how did you get rid of the 5?

    • one year ago
  7. mushinni Group Title
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    in the last step

    • one year ago
  8. Ken&Riss Group Title
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    He got rid of the 5 by putting 2 into 5 twice, and it had a remainder of 1, so it came out as n2

    • one year ago
  9. tem0c_00 Group Title
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    I still don't get it

    • 11 months ago
  10. tem0c_00 Group Title
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    can I plz get some help

    • 11 months ago
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