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jennwatso15

  • one year ago

how many different permutations are thereof the set {a, b, c, d, e, f, g}

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  1. satellite73
    • one year ago
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    seven elements in the set, so \(7!\) i.e. seven factorial

  2. satellite73
    • one year ago
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    \[7!=7\times 6\times 5\times 4\times 3\times 2\times 1\]

  3. goformit100
    • one year ago
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    |dw:1361345423099:dw|

  4. goformit100
    • one year ago
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    |dw:1361345442511:dw|

  5. satellite73
    • one year ago
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    seven choices for the first number then six for the second five for the third four for the fourth 3 for the fifth 2 for the sixth 1 for the last counting principle tells you to multiply the number of choices together

  6. jennwatso15
    • one year ago
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    thats what i thought but its always good to double check because this book doesn't have the answers in the back thanks :D

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