A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Help Please. 4^2x+3=1
anonymous
 3 years ago
Help Please. 4^2x+3=1

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need help badly in couple of questions, someone please help!!

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1is the problem \[\Large 4^{2x}+3=1\] OR is it \[\Large 4^{2x+3}=1\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1Hint: \[\Large 4^{2x+3}=1\] \[\Large 4^{2x+3}=4^0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so we are not using that 1?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1we are, just a different form of it 4^0 is the same as 1

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1the bases are the same (4) so the exponents must be the same

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup i Got the answer thanks :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you please help me with couple of them too?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1sure a few more

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok here is another one

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\] \[10^{3x}\times10^{x}=10^{1}\] \[10^{3x+x}=10^{1}\] I'll let you finish

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1what do you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x=\frac{ 1 }{ 2 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I need help with couple more pleaseeee!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[64\times16^{3x}=16^{3x2}\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.13x + x = 1 2x = 1 x = 1/2 good

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[64\times16^{3x}=16^{3x2}\] \[(4^3)\times(4^2)^{3x}=(4^2)^{3x2}\] \[(4^3)\times4^{2(3x)}=(4)^{2(3x2)}\] \[(4^3)\times4^{6x}=(4)^{6x4}\] \[4^{3+(6x)}=(4)^{6x4}\] \[4^{36x}=(4)^{6x4}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got an answer: \[x=\frac{ 7 }{ 12 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 81^{3n+2} }{ 243^{n} }=3^{4}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh maybe I can do this one let me try first :)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1alright, tell me what you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I got \[\frac{ 4 }{ 17 }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[81\times9^{2b2}=27\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1tell me what you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh I got that one \[\frac{ 3 }{ 4 }\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1good, that's correct

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}1 \\ 6\end{matrix}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\]

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1and what did you get

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I m having trouble starting it but still trying

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1\[\Large \left(\frac{1}{6}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\] \[\Large \left(6^{1}\right)^{3x+2}\times(6^3)^{3x}=6^{3}\] \[\Large \left(6\right)^{(3x+2)}\times(6)^{9x}=6^{3}\] \[\Large 6^{(3x+2)+9x}=6^{3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh I only messed up with one sign
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.