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Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
I need help badly in couple of questions, someone please help!!
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
is the problem \[\Large 4^{2x}+3=1\] OR is it \[\Large 4^{2x+3}=1\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
yeah that second one
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Hint: \[\Large 4^{2x+3}=1\] \[\Large 4^{2x+3}=4^0\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
so we are not using that 1?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
we are, just a different form of it 4^0 is the same as 1
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
the bases are the same (4) so the exponents must be the same
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
so 2x + 3 = 0
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
yup i Got the answer thanks :)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
ok great
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
can you please help me with couple of them too?
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
sure a few more
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
ok here is another one
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\] \[10^{3x}\times10^{x}=10^{1}\] \[10^{3x+x}=10^{1}\] I'll let you finish
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
what do you get
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[x=\frac{ 1 }{ 2 }\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
I need help with couple more pleaseeee!!
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[64\times16^{3x}=16^{3x2}\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
3x + x = 1 2x = 1 x = 1/2 good
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
\[64\times16^{3x}=16^{3x2}\] \[(4^3)\times(4^2)^{3x}=(4^2)^{3x2}\] \[(4^3)\times4^{2(3x)}=(4)^{2(3x2)}\] \[(4^3)\times4^{6x}=(4)^{6x4}\] \[4^{3+(6x)}=(4)^{6x4}\] \[4^{36x}=(4)^{6x4}\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
I got an answer: \[x=\frac{ 7 }{ 12 }\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
good
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{ 81^{3n+2} }{ 243^{n} }=3^{4}\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
oh maybe I can do this one let me try first :)
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
alright, tell me what you get
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
I got \[\frac{ 4 }{ 17 }\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you nailed it
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[81\times9^{2b2}=27\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
tell me what you get
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
oh I got that one \[\frac{ 3 }{ 4 }\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
good, that's correct
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}1 \\ 6\end{matrix}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
and what did you get
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
I m having trouble starting it but still trying
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
\[\Large \left(\frac{1}{6}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\] \[\Large \left(6^{1}\right)^{3x+2}\times(6^3)^{3x}=6^{3}\] \[\Large \left(6\right)^{(3x+2)}\times(6)^{9x}=6^{3}\] \[\Large 6^{(3x+2)+9x}=6^{3}\]
 one year ago

Pinky1234 Group TitleBest ResponseYou've already chosen the best response.1
oh I only messed up with one sign
 one year ago
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