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Pinky1234Best ResponseYou've already chosen the best response.1
I need help badly in couple of questions, someone please help!!
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
is the problem \[\Large 4^{2x}+3=1\] OR is it \[\Large 4^{2x+3}=1\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
yeah that second one
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
Hint: \[\Large 4^{2x+3}=1\] \[\Large 4^{2x+3}=4^0\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
so we are not using that 1?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
we are, just a different form of it 4^0 is the same as 1
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
the bases are the same (4) so the exponents must be the same
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
so 2x + 3 = 0
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
yup i Got the answer thanks :)
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
can you please help me with couple of them too?
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
sure a few more
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
ok here is another one
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[10^{3x}\times10^{x}=\frac{ 1 }{ 10 }\] \[10^{3x}\times10^{x}=10^{1}\] \[10^{3x+x}=10^{1}\] I'll let you finish
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
what do you get
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[x=\frac{ 1 }{ 2 }\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
I need help with couple more pleaseeee!!
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[64\times16^{3x}=16^{3x2}\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
3x + x = 1 2x = 1 x = 1/2 good
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[64\times16^{3x}=16^{3x2}\] \[(4^3)\times(4^2)^{3x}=(4^2)^{3x2}\] \[(4^3)\times4^{2(3x)}=(4)^{2(3x2)}\] \[(4^3)\times4^{6x}=(4)^{6x4}\] \[4^{3+(6x)}=(4)^{6x4}\] \[4^{36x}=(4)^{6x4}\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
I got an answer: \[x=\frac{ 7 }{ 12 }\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[\frac{ 81^{3n+2} }{ 243^{n} }=3^{4}\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
oh maybe I can do this one let me try first :)
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
alright, tell me what you get
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
I got \[\frac{ 4 }{ 17 }\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you nailed it
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[81\times9^{2b2}=27\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
tell me what you get
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
oh I got that one \[\frac{ 3 }{ 4 }\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
good, that's correct
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
\[\left(\begin{matrix}1 \\ 6\end{matrix}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\]
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
and what did you get
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
I m having trouble starting it but still trying
 one year ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
\[\Large \left(\frac{1}{6}\right)^{3x+2}\times216^{3x}=\frac{ 1 }{ 216 }\] \[\Large \left(6^{1}\right)^{3x+2}\times(6^3)^{3x}=6^{3}\] \[\Large \left(6\right)^{(3x+2)}\times(6)^{9x}=6^{3}\] \[\Large 6^{(3x+2)+9x}=6^{3}\]
 one year ago

Pinky1234Best ResponseYou've already chosen the best response.1
oh I only messed up with one sign
 one year ago
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